420 likes | 566 Views
Chapter 8 Similarity. 232 Geometry BEHS Mrs. Prescott. Ratios. Ratio – a comparison of 2 numbers in the same unit of measure Example: 2 females to 3 males 2 to 3 2:3. Simplifying Ratios. Reduce using common factors as you would simplify any fraction Pages 461-462 12. 16. 22. 26.
E N D
Chapter 8 Similarity 232 Geometry BEHS Mrs. Prescott
Ratios • Ratio – a comparison of 2 numbers in the same unit of measure • Example: 2 females to 3 males • 2 to 3 • 2:3
Simplifying Ratios • Reduce using common factors as you would simplify any fraction • Pages 461-462 12. 16. 22. 26.
Proportions • Proportion – a statement equating 2 ratios • Example: • Also written - • 3:6 = 5:10 means extremes
Proportions • The product of the means is equal to the product of the extremes • 3:6 = 5:10 • The cross products in a proportion are always equal which is why we cross multiply to solve a proportion 65 310 • 310 = 65 • 30 = 30
Solve the Proportion -4x -4x
Properties of Proportions • Cross Product Property • The Product of the extremes equals the product of the means. • Reciprocal Property • If two ratios are equal, then their reciprocals are also equal.
Page 463 #56. -7k -7k 3 3
Extended Ratios • Simplify the extended ratio of the 4 sides of the quadrilateral. • 20:16:40:36 = • 5:4:10:9 20cm 16cm 36cm 40cm
Examples: Side lengths are 9 ft, 12 ft, 9 ft, and 12 ft. • The perimeter of a parallelogram is 42ft, and ratio of 2 of its unequal sides is 3:4. Find each side length. 4 sides – 3:4: 3:4 or 3x:4x:3x:4x 3x + 4x + 3x + 4x = 42 14x = 42 x = 3 • If the extended ratio of the angles of a triangle are 5:6:7, find each angle measure. 5x:6x:7x 5x + 6x + 7x = 180 18x = 180 x = 10 Angle measures are 50º, 60º, 70º,
Section 8.2 Problem Solving in Geometry with Proportions Page 465 232 Geometry BEHS, Mrs. Prescott
Additional Properties of Proportions: Ex. ¾ =9/12, then 3/9=4/12 • If • If Ex. ¾ = 9/12, then (3+4)/4 = (9+12)/12 7/4 = 21/12
Examples: True True or False. Complete the statement. False 15 m+9
Example – page 469 J K 2 5 26. P Q 7 x 9 X + 5 S -7x -7x
Geometry Mean - definition The geometric mean of 2 positive numbers a and b is the positive number x such that
Geometry Mean-Example Find the geometric mean of 3 and 48. √ √
Geometry Mean-Example Find the geometric mean between 6 and 15.
Section 8.3 Similar Polygons Madeleine Wood Page 473 232 Geometry BEHS, Mrs. Prescott
Similar Polygons • Definition: Similar Polygons – 2 polygons such that: • their corresponding angles are congruent • the lengths of their corresponding sides are proportional • Symbol:
Similar Polygons Example: • You can see that the corresponding angles are congruent. • Corresponding sides are in proportion means that the ratios of every 2 pairs of corresponding sides are equal. They all reduce to ½ , which is called the scale factor.
Similarity Statement: ABCD~EFGH The order of the vertices indicates which angles correspond and which segments correspond in the similarity statement. To write a proportionality statement, write the ratios of all pairs of corresponding sides. List all pairs of congruent corresponding angles. Write the proportionality statement.
Examples: Page 475 Rotate to make it easier to match the corresponding sides 8 3 15 10 No, because 15/10≠ 8/3 Yes, all corr. ∡s are ≅ and the ratios of all corr. sides are =.
Examples: Page 475. Given: TUVW~ABCD ∡A≅∡T, ∡B≅∡U, ∡C≅∡V, ∡D≅∡W, and 9 B A Scale factor of ABCD to TUVW 6 70º D D C Scale factor of TUVW to ABCD is 5/3 15 U T V W 23
Examples: Page 475 6. 7. Find all missing segment lengths and angle measures. 9 B A 110º 110º 6 6 70º 70º D C y 15 U T 110º 110º =10 10 x 70º 70º V W 23
Given that ΔRST~ΔJKL. find the value of x and y. 70º 70º 50º (2w-5)º 70 + 50 + (2w – 5) = 180 115 + 2w = 180 2w = 65 w = 32.5
Complete each. • Find the scale factor of the triangles. • Find the lengths of the missing segment lengths. • Find the perimeter of each triangle. • Find the ratio of the perimeter of the 2 triangles.
Similar Polygon Perimeter Theorem If 2 polygons are similar, then the ratio of their perimeters is equal to the ratios of their corresponding side lengths.
Given that ΔRSV~ΔRTU, answer each of the following. • Write the statement of proportionality. • m∡RSV=_______, m∡U= _______ • RS = ______ RT=______ SV= ______ RV=______ R 80º 5 80˚ 70˚ S V 8 10 15 5 70º T U 4 4 12
AA ~ Postulate • If 2 angles of one triangle are congruent to two angles of another triangle, then the two triangles are similar. • Given that ∡D ≅ ∡A and ∡C ≅ ∡F, then ΔABC ~ ΔDEF. D A C B F E
Chapter 8- Section 8.5 Proving Triangles are Similar Page 488 232 Geometry Mrs. Prescott BEHS
SSS ~ Theorem • If the lengths of the corresponding sides of two triangles are proportional, then the two triangles are similar. D A 9 6 6 4 C B F E 8 12
SAS ~ Theorem If an angle of one triangle is congruent to an angle of a 2nd triangle, and the lengths of the sides including these angle are proportional, then the two triangles are similar. D A 6 9 38º C 8 B 38º F 12 E
Practice Problems: page 492 #2-5 • AA~ Post., ΔABC ~ΔDEF • SAS~ Thm., ΔABC ~ΔDFE • Both ΔJKL and ΔMNP; SSS~ • Ratio = 1:6, the triangles are similar by SSS~
Chapter 8- Section 8.6 Proportions and Similar Triangles Page 498 232 Geometry Mrs. Prescott BEHS
Triangle Proportionality Theorem A line that intersects 2 sides of a triangle is parallel to the 3rd side if and only if it divides the 2 sides proportionally. R 5 4 S V 8 10 and T U
Theorem: If 3 parallel lines intersect two transversals, then they divide the transversals proportionally. A B D C F E
Example: Solve for x and y.
Theorem: • If a ray bisects an angle of a triangle, then it divides the opposite side into segments whose lengths are proportional to the lengths of the other 2 sides. D 3 9 G 4 F E 12
Find the value of A. Example: