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Lecture # 9. Stress Concentrations. Objective:. To find stress within a member of abrupt change in shape. Stress Concentrations Factors. Figure:. Figure:. Example:.
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Lecture # 9 Stress Concentrations Objective: To find stress within a member of abrupt change in shape.
Example: A steel bar has the dimensions as shown in figure. If the allowable stress is allow = 115 MPa, determine the largest axial force P that the bar can carry.
Solution: Because there is a shoulder fillet, the stress-concentration factor can be determined using the graph as in the previous figure. Calculating the necessary geometric parameters yields Thus, from the graph, K = 1.4
Solution: Computing the average normal stress at the smallest cross-section, we have Applying equation with allow = max yield allow = Kavg 115 N/mm2 = 1.4(0.005 P) P = 16.43 (103) N Ans….. = 16.43 kN
Problem: • Determine the maximum normal stress developed in the bar when it is subjected to a tension of P = 8 kN. • If the allowable normal stress for the bar is allow = 120 MPa, determine the maximum axial force P that can be applied to the bar.