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The Mole & Formulas

The Mole & Formulas. Dr. Ron Rusay. Mole - Mass Relationships Chemical Reactions Stoichiometry. The Mole % Composition: Determining the Formula of an Unknown Compound Writing and Balancing Chemical Equations Calculating the amounts of Reactant and Product Limiting Reactant. The Mole.

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The Mole & Formulas

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  1. The Mole & Formulas Dr. Ron Rusay

  2. Mole - Mass Relationships Chemical Reactions Stoichiometry • The Mole • % Composition: Determining the Formula of an Unknown Compound • Writing and Balancing Chemical Equations • Calculating the amounts of Reactant and Product • Limiting Reactant

  3. The Mole • The numberof carbon atoms in exactly 12 grams of pure 12C. The numberequals 6.02  10 23 • 1 mole of anything = 6.02  10 23 units • 6.02  10 23“units” of anything: atoms, people, stars, $s, etc., etc. = 1 mole

  4. Avogadro’s Number Avogadro’s number equals 1 mole….which equals 6.022  1023“units”

  5. Counting by Weighing 12 red marbles @ 7g each = 84g 12 yellow marbles @4g each=48g 55.85g Fe = 6.022 x 1023 atoms Fe 32.07g S = 6.022 x 1023 atoms S

  6. Relative Masses of 1 Mole CaCO3 100.09 g Oxygen 32.00 g Copper 63.55 g Water 18.02 g

  7. Atomic and Molecular WeightsMass Measurements • 1H weighs 1.6735 x 10-24 g and 16O 2.6560 x 10-23 g. • DEFINITION: mass of 12C = exactly 12 amu. • Using atomic mass units: • 1 amu = 1.66054 x 10-24 g • 1 g = 6.02214 x 1023 amu

  8. QUESTION

  9. E) 1.06 10 g A mole of copper atoms has a mass of 63.55 g. The mass of 1 copper atom is 63.55 g/(6.022 10 ) = 1.06 10 g. ANSWER – 22 ´ 23 – 22 ´ ´

  10. Atomic and Molecular Weights • Formula Weight a.k.a. Molecular Weight • Formula weights (FW): sum of Atomic Weights (AW) for atoms in formula. • FW (H2SO4) = 2AW(H) + AW(S) + 4AW(O) • = 2(1.0 amu) + (32.0 amu) + 4(16.0) • = 98.0 amu

  11. Atomic and Molecular Weights • Molecular weight (MW) is the weight of the molecular formula in amu. • MW of sugar (C6H12O6 ) = ? • MW = 6(12.0 amu) + 12(1.0 amu) + 6(16.0 amu) • = 180 amu

  12. Molar Mass • A substance’s molar mass (equal to the formula weight: atomic or molecular weight in grams) is the mass in grams of one mole of the element or compound. • C = 12.01 grams per mole (g/mol) • CO2 = ?? • 44.01 grams per mole (g/mol) 12.01 + 2(16.00) = 44.01

  13. QUESTION

  14. C) 46.07 The molar mass is the sum of masses of all the atoms in the molecule. 2 12.01 + 6 1.008 + 1 16.00 = 46.07 ANSWER ´ ´ ´

  15. QUESTION

  16. C) CH Cl The molar mass has units of g/mol. (12.8 g/0.256 mol) = 50.0 g/mol. The molecule with the closest molar mass is CH ANSWER 3 Cl. 3

  17. QUESTION

  18. B) 278 g The molar mass of sodium hydroxide, NaOH, is 22.99 g/mol + 16.00 g/mol + 1.008 g/mol = 40.00 g/mol. Convert to grams: 6.94 mol (40.00 g/mol) = 278 g. ANSWER ´

  19. Percent Composition • Mass percent of an element: • For iron in (Fe2O3), iron (III) oxide = ?

  20. QUESTION

  21. E) A ll of these The ratio of C to H in C H is 1:1. This is the same ratio found for each of the compounds, so all have the same percent composition by mass. ANSWER 8 8

  22. QUESTION Morphine, derived from opium plants, has the potential for use and abuse. It’s formula is C17H19NO3. What percent, by mass, is the carbon in this compound? 42.5% 27.9% 71.6% This cannot be solved until the mass of the sample is given.

  23. ANSWER Morphine, derived from opium plants, has the potential for use and abuse. It’s formula is C17H19NO3. What percent, by mass, is the carbon in this compound? 42.5% 27.9% 71.6% This cannot be solved until the mass of the sample is given. (17  12) / ((17  12) + (19  1) + (1  14) + 3  16)) = 0.716 0.716  100 = 71.6 %

  24. QUESTION

  25. C) 4.04 g The molar mass of K CrO is 2 39.10 + 52.00 + 7 16.00 = 242.2. The mass fraction of potassium is (2 39.10)/242.2 = 0.3229. 0.3229 12.5 g = 4.04 g. ANSWER ´ 2 7 ´ ´ ´

  26. Formulas: Dalton’s Law • Dalton’s law of multiple proportions: When two elements form different compounds, the mass ratio of the elements in one compound is related to the mass ratio in the other by a small whole number.

  27. Formulas: Multiple Proportions

  28. Formulas & Multiple ProportionsComponents of acid rain, SO2(g) and SO3(g) • Compound A contains: 1.000 g Sulfur & 1.500 g Oxygen • Compound B contains: 1.000 g Sulfur & 1.000 g Oxygen • Mass ratio A: 2 to 3; Mass ratio B: 1 to 1 • Adjusting for atomic mass differences: AW sulfur is 2x the AW oxygen; the atom ratios therefore are S1O3 and S1O2 respectively

  29. Formulas &Molecular Representations • molecular formula = C6H6Benzene • empirical formula = CH = C6/6H6/6 • molecular formula = (empirical formula)n [n = integer] (CH)6 • Other representations: Lewis Dot formulas, structural formulas, 2-D, 3-D

  30. Formulas &Molecular Representations

  31. Empirical Formulas from Analyses

  32. Empirical Formula Determination • 1. Use percent analysis. Let 100 % = 100 grams of compound. • 2. Determine the moles of each element. (Element % = grams of element.) • 3. Divide each value of moles by the smallest of the mole values. • 4. Multiply each number by an integer to obtain all whole numbers.

  33. QUESTION The dye indigo is a compound with tremendous economic importance (blue jeans wouldn’t be blue without it.) Indigo’s percent composition is: 73.27% C; 3.84% H; 10.68%N and 12.21% O. What is the empirical formula of indigo? C6H4NO C8H3NO C8H5NO I know this should be whole numbers for each atom, but I do not know how to accomplish that.

  34. ANSWER The dye indigo is a compound with tremendous economic importance (blue jeans wouldn’t be blue without it.) Indigo’s percent composition is: 73.27% C; 3.84% H; 10.68%N and 12.21% O. What is the empirical formula of indigo? C6H4NO C8H3NO C8H5NO I know this should be whole numbers for each atom, but I do not know how to accomplish that.

  35. Empirical & Molecular Formula Determination Quinine: C 74.05%, H 7.46%, N 8.63%, O 9.86% • 74.05/12.01, 7.46/1.008, 8.63/14.01, 9.86/16.00 C6.166 H7.40 N0.616 O0.616 • Empirical Formula: C10 H12 N1 O1 Empirical Formula Weight = ? • Molecular Weight = 324.42 Molecular Formula = 2x empirical formula • Molecular Formula = C20 H24 N2 O2

  36. A Mass Spectrometer Records a mass spectrum

  37. http://www.colby.edu/chemistry/OChem/demoindex.html#table

  38. A mass spectrum records only positively charged fragments m/z = mass to charge ratio of the fragment

  39. QUESTION http://chemconnections.org/pdb/Quinine.html From the structures, determine the molecular formula of quinine. A Carbon atom is at each angle. Each C has 4 bonds (lines + Hs). Hs are not always drawn in & must be added. A)C18H24NO2 B)C20H20NO3C)C20H24N2O2D)C20H26N2O2

  40. ANSWER http://chemconnections.org/pdb/Quinine.html From the structures, determine the molecular formula of quinine. C = 20 H = 24 N = 2 O =2 A Carbon atom is at each angle. Each C has 4 bonds (lines + Hs). Hs are not always drawn in & must be added. C20H24N2O2 A)C18H24NO2 B)C20H20NO3C)C20H24N2O2D)C20H26N2O2

  41. QUESTION

  42. ANSWER B) C H 8 8 The mass of CH is 13.018. 13.018 divides into 104.1 about 8 times. Therefore there are 8 CH groups in this compound. C H is the molecular 8 8 formula.

  43. QUESTION Examine the condensed structural formulas shown below: I) Acetic acid (main ingredient in vinegar), CH3COOH II) Formaldehyde (used to preserve biological specimens), HCHO III) Ethanol (alcohol in beer and wine), CH3CH2OH For which molecule(s) are the empirical formula(s) and the molecular formula(s) the same? A) II B) I and II C) II and III D) I, II, and III

  44. ANSWER Examine the condensed structural formulas shown below: I) Acetic acid (main ingredient in vinegar), CH3COOH II) Formaldehyde (used to preserve biological specimens), HCHO III) Ethanol (alcohol in beer and wine), CH3CH2OH For which molecule(s) are the empirical formula(s) and the molecular formula(s) the same? A) II B) I and II C) II and III D) I, II, and III

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