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Counting Outcomes Permutations & Combinations Probability Review

Counting Outcomes Permutations & Combinations Probability Review. 8/21. Counting Outcomes. Andy has 3 pairs of pants: 1 gray, 1 blue and 1 black. He has 2 shirts: 1 white and 1 red. If Andy picks 1 pair of pants and 1 shirt, how many different outfits does he have ?

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Counting Outcomes Permutations & Combinations Probability Review

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  1. Counting OutcomesPermutations & CombinationsProbabilityReview

  2. 8/21 Counting Outcomes Andy has 3 pairs of pants: 1 gray, 1 blue and 1 black. He has 2 shirts: 1 white and 1 red. If Andy picks 1 pair of pants and 1 shirt, how many different outfits does he have? Andy can choose 1 of 3 pairs of pants and 1 of 2 shirts. A tree diagram can help you count his choices.

  3. The total number of choices is the product of the number of choices for item A, the number of choices for item B, etc. You can also use the counting principle. FIRST ● SECOND ● THIRD, etc. = TOTAL NUMBER OF CHOICES

  4. Find the total number of choices. 1. Moesha has 6 pairs of socks and 2 pairs of sneakers. She chooses 1 pair of socks and 1 pair of sneakers. How many possible combinations are there? 2. Kim has 5 swimsuits, 3 pairs of sandals, and 2 beach towels. In how many ways can she pick one of each to go to the beach with?

  5. Permutations • The expression 5! is read “5 factorial”. • It means the product of all whole numbers from 5 to 1.5! = • Evaluate

  6. How many 3-letter codes can be made from A, B, C, D, E, F, G, H with no repeating letters? • This is a permutation problem. ORDER IS IMPORTANT. ABC is different from ACB. • There are choices for the first letter. • There are choices for the second letter. • There are choices for the third letter.

  7. You can write the code as , meaning the number of permutations of 8 objects chosen at 3 times. • The number of codes possible x x= Permutation Formula • n is the number of objects and r is the number chosen.

  8. 1. 2. 3. 4. 5. 6. 7. 8. Evaluate each factorial. Find the value of each expression.

  9. Solve. 9. In how many ways can you pick a football center and quarterback from 6 players who try out? 10. For a meeting agenda, in how many ways can you schedule 3 speakers out of 10 people who would like to speak?

  10. Combinations Mr. Jones wants to pick 2 students from Martin, Joan, Bart, Esperanza, and Tina to demonstrate an experiment. How many different pairs of students can he choose? In this combination problem, the ORDER DOES NOT MATTER. What are the possibilities? There are possible combinations.

  11. Combination Formula • n is the number of objects and r is the number chosen • The number of combinations of 5 students taken 2 at a time is:

  12. 1. 2. 3. 4. Find the number of combinations:

  13. Solve. 5. In how many ways can Susie choose 3 of 10 books to take with her on a trip? 6. In how many ways can Rosa select 2 movies to rent out of 6 that she likes?

  14. 8/19 • Probability: • Notation: P(event) • Theoretical Probability: • The likelihood of an event occurring. • Equation: # of favorable outcomes # of total outcomes • Experimental Probability: • The number of times an event occurs in an experiment. • Equation: # of trials an outcome occurs total # of trials

  15. INDEPENDENT EVENT DEPENDENT EVENT • An event who’s outcome is based on a previous outcome. Spinning a spinner, and then rolling a dice Draw a card, keep it, then drawing another card. • An event who’s outcome is NOT based on a previous outcome.

  16. WITH REPLACEMENT P(A and B) = P(A) • P(B) A bag of marbles contains 6 blue, 5 red, 3 green, 4 orange, and 2 purple. You draw a marble at random, record your findings, replace the marble, then draw again. Find Ex) P(blue, blue) = You Try a) P(purple, orange) = b) P(black, blue) =

  17. WITHOUT REPLACEMENT P(A and B after A) = P(A) • P(B after A) A sock drawer contains 4 black, 2 yellow, 3 polk-a-dot, 5 Nike, and 6 pink. You pick a sock at random, record your findings, then pick another withoutreplacing the first. • Find • Ex) P(yellow, pink) = • You Try • a) P(black, black) = b) P(Nike, pink) =

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