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A uniform sphere with a radius of 12cm and a mass of 6.0kg is released from rest at the top of a ramp. The ramp is 1.5m high, and 9.5m long. If the ball rolls without slipping, what will be its speed at the bottom of the ramp?. v f. 1.5m. 9.5m. ∑ τ =I α. n. fR= R 2 α. f. mg x. fR= R 2.
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A uniform sphere with a radius of 12cm and a mass of 6.0kg is released from rest at the top of a ramp. The ramp is 1.5m high, and 9.5m long. If the ball rolls without slipping, what will be its speed at the bottom of the ramp? vf 1.5m 9.5m
∑τ=Iα n fR=R2α f mgx fR=R2 θ mgy f=a mg ∑F=ma mgx- f=ma OR…
Kinetic Energy (again) For a rotating object:
Ei= Ef (KEt + KEr +PE) i = (KEt + KEr +PE) f HW: read pp.246-249; Do 40,42