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Altitudes and Medians. Median of A meets the mid point of BC. A. B. ( , ). x 1 +x 2 y 1 +y 2. Median. C. 2 2. m 1 m 2 = -1. Altitude. A. B. C. Altitude of A meets BC at right angles. A. Altitude from B. B. median from C. C. Altitudes and Medians.
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Median of A meets the mid point of BC A B ( , ) x1+x2 y1+y2 Median C 2 2
m1m2 = -1 Altitude A B C Altitude of A meets BC at right angles
A Altitude from B B median from C C
Altitudes and Medians Altitude of A meets BC at right angles A m1m2 = -1 B ( , ) x1+x2y1+y2 2 2 C Median of A meets the mid point of BC
A(2,1) B(5,8) C(9,6) are vertices of ABC Find equation of Altitude through B Need m and (a,b) ? perpendicular to AC C(9,6) √ mAC =6 - 1 = 5/7 9 – 2 B(5,8) maltB = - 7/5 A(2,1) use y – b = m(x – a)
A(2,1) B(5,8) C(9,6) are vertices of ABC Find equation of Median through A √ Need m and (a,b) ? find mid point C(9,6) √ √ T (7 , 7) T = (7 , 7) B(5,8) find mAT either point will do A(2,1) use y – b = m(x – a)
and Finally Perpendicular Bisector cut in half at right angles x1+x2y1+y2 2 2 m1m2 = -1