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Complex Numbers? What’s So Complex?. Complex numbers are vectors. represented in the complex plane as the sum of a Real part and an Imaginary part : z = a + b i Re(z) = a ; Im(z) = b. Just like vectors!. |z| = (a 2 + b 2 ) 1/2 is length or magnitude, just like vectors.
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Complex numbers are vectors represented in the complex plane as the sum of a Real part and an Imaginary part: z = a + bi Re(z) = a; Im(z) = b
Just like vectors! |z| = (a2 + b2)1/2 is length or magnitude, just like vectors. a = tan-1 (b/a) is direction, just like vectors!
Just like vectors! For two complex numbers a + bi and c + di: Addition/subtraction combines separate components, just like vectors.
Useful identities Euler: eix = cos x + i sin x cos x = (eix + e-ix)/2 sin x = (eix - e-ix)/2i
Sure, he’s French, but we must give props: DeMoivre: (cos x + i sin x)n = cos (nx) + i sin (nx) cos 2x + i sin 2x = ei2x cos 2x = (1 + cos 2x)/2 sin 2x = (1 - cos 2x)/2
What about multiplication? Just FOIL it!
Multiplication: the hard way! z1z2= r1 (cosa1 + i sina1) r2 (cosa2 + i sina2) = r1 r2 (cosa1 cosa2 - sina1 sina2) + i r1 r2 (cosa1 sina2 + cosa2 sina1) = r1 r2 [cos(a1 + a2) + i sin(a1 + a2)]
Multiplication: the easy way! “Neither dot nor cross do you multiply complex numbers by.”
Multiplication: by i Rotate by 90o and swap Re and Im
i ‘s all over the Unit Circle! Note i4 = 1 does not mean that 0 = 4
i ‘s all over the Unit Circle! Did you see i½?
Square root of i? Find the square root of 7+24 i. (Hint: it’s another complex number, which we’ll call u+vi). Which can be solved by ordinary means to yield 4+3i and -4 - 3i.
Complex Conjugates Complex conjugates reflect in the Re axis.
Complex Reciprocals The reciprocal of a complex number lies on the same ray as its conjugate!
Powers of z The graph of f(z)=zn for |z|<1 is called an exponential spiral.
The rotation comes from our old buddy DeMoivre: Raising a unit z to the nth power is multiplying its angle by n. (cos x + i sin x)n = cos (nx) + i sin (nx)
How about a slice of p: Roots of z If z3 = 3+3i = 4.24eip/4then Each successive nth root is another 2p/n around the circle.
Find the roots of the complex equation z2 + 2i z + 24 = 0 Sounds like a job for the quadratic formula!
Was that so complex? And never forget, epi = -1