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WORK

WORK. Work changes the energy of a system by applying an external force through a displacement ( x). F. . Fcos =F //. x. Δ x. W = F • r = Fxcos = F // x. Units: Nm = Joule (J) W = Work F // = The force parallel to the displacement x = displacement. F (N). Work (Energy).

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WORK

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  1. WORK

  2. Work changes the energy of a system by applying an external force through a displacement (x).

  3. F  Fcos=F// x Δx W = F•r = Fxcos = F// x Units: Nm = Joule (J) W = Work F// = The force parallel to the displacement x = displacement

  4. F (N) Work (Energy) x (m) Graphically work is equal to the area under the graph of force (F) vs. position (x).

  5. 20N 5m Example 1: Calculate the work done by the 20N force. W = Fx cos = (20N)(5m)(cos 0) = 100 Nm

  6. 20N 30 5m Example 2: Calculate the work done by the 20N force. W = Fx cos = (20N)(5m)(cos 30) = 86.6 Nm

  7. 20N 5m Fg Example 3: Calculate the work done by the 20N force. W = Fx cos = (20N)(5m)(cos 90) = 0 Nm

  8. 20N 5m 30 Example 4: Calculate the work done by the 20N force. W= Fx cos = (20N)(5m)(cos 0) = 100 Nm

  9. 5m 35kg Example 5: A rope applies a tension of 400N to a 35kg crate. Assuming the crate starts from rest find the velocity of the crate after being raised 5 meters. (Neglect friction) 400N

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