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If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the perimeter measurement?. If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the perimeter measurement? inches.
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If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the perimeter measurement?
If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the perimeter measurement? inches
If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the area of a face measurement? inches
If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the area of a face measurement? inches inches²
If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the volume measurement? inches inches²
If we had a rectangular prism that was 3 inches by 4 inches by 6 inches what would be the units of the volume measurement? inches inches² inches³
If we double (x2)all the side measurements, what happens to the perimeter? sides inches inches² inches³ x2
If we double (x2)all the side measurements, what happens to the area? sides inches inches² inches³ x2 x2
If we double (x2)all the side measurements, what happens to the volume? sides inches inches² inches³ x2 x2 x2²
If we double (x2)all the side measurements, what happens to the volume? sides inches inches² inches³ x2 x2 x2² x2³
If we quadrupled (x4)all the side measurements, what happens to the perimeter, area and volume? sides inches inches² inches³ x2 x2 x2² x2³
If we quadrupled (x4)all the side measurements, what happens to the perimeter, area and volume? sides inches inches² inches³ x2 x2 x2² x2³ x4 x4 x4² x4³
Tuesday, April 22 Chapter 11 Review
A paperweight has a triangular base with an area of 15 square meters. If the height is 1.5 meter, what is the volume of the paperweight?
A paperweight has a triangular base with an area of 15 square meters. If the height is 1.5 meter, what is the volume of the paperweight? Since the base has an area of 15 m² , you just multiply by the height. V = Bh 15 m² · 1.5m = 22.5 m³
Chapter 11 Review 1. A shop records the number of specialty shirts sold each month. What is the mean number of T-shirts sold? A. 75 B. 83 C. 85 D. 92
Chapter 11 Review 1. A shop records the number of specialty shirts sold each month. What is the mean number of T-shirts sold? A. 75 B. 83 C. 85 D. 92 75 + 68 + 75 + 92 + 105 = 415 ÷ 5 = 83 Answer: B
Chapter 11 Review 2. Javon’s bill at the bakery was $12. He bought 12 egg bagels for $0.50 each. If an onion bagel costs $0.75, how can he find how much he spent on onion bagels? F. Add $0.50 and $0.75. G. Subtract the product of 12 and $0.50 from $12.00. H. Multiply $0.75 and 12. I. Divide 12 by $0.50.
Chapter 11 Review 2. Javon’s bill at the bakery was $12. He bought 12 egg bagels for $0.50 each. If an onion bagel costs $0.75, how can he find how much he spent on onion bagels? F. Add $0.50 and $0.75. G. Subtract the product of 12 and $0.50 from $12.00. H. Multiply $0.75 and 12. I. Divide 12 by $0.50. $12 - 12 · $.50 = x· $.75 Answer: G
Chapter 11 Review 3. What is the median of the following ages of people attending a concert: 2, 7, 41, 25, 19, 22, 28, 32, and 24? A. 17 B. 22 C. 24 D. 41
Chapter 11 Review 3. What is the median of the following ages of people attending a concert: 2, 7, 41, 25, 19, 22, 28, 32, and 24? A. 17 B. 22 C. 24 D. 41 2, 7, 19, 22, 24, 25, 28, 32, 41 Answer: C
Chapter 11 Review 4. GRIDDED RESPONSE Teresa had a family photo with the dimensions of 12 inches by inches. Find the area of the photo, in square inches.
Chapter 11 Review 4. GRIDDED RESPONSE Teresa had a family photo with the dimensions of 12 inches by inches. Find the area of the photo, in square inches. A = 12 in · 16
Chapter 11 Review 5. GRIDDED RESPONSE Use the frequency table below to determine the mean number of hours of sleep.
Chapter 11 Review 5. GRIDDED RESPONSE Use the frequency table below to determine the mean number of hours of sleep. Mean: 6.85 5+ 5+ 5.5+ 6+ 6+ 6+ 6.5+ 7+ 7+ 7+ 7+ 7+ 7.5+ 7.5+ 7.5+ 7.5+ 8+ 8+ 8+ 8=137 137 ÷ 20 = 6.85
Chapter 11 Review 6. Martha was making place cards fora party that used of a piece of papereach. If she needed to make place cardsfor 31 people, how many pieces of paperwould she need? F. 93 G. 34 H. 11 I. 10
Chapter 11 Review 6. Martha was making place cards fora party that used of a piece of papereach. If she needed to make place cardsfor 31 people, how many pieces of paperwould she need? F. 93 G. 34 H. 11 I. 10 31 x = 10 Answer: H
Chapter 11 Review 7. The lengths of the longest bridges in the United States are shown. Which statement is supported by the data? A. If the lengths of the bridges were distributed equally among all five bridges, each would measure 95,250 feet in length. B. There is no bridge length that occurs more often than another. C. The lengths of the bridges have a range of 82,000 feet. D. The majority of the bridges are greater than 97,000 feet in length.
Chapter 11 Review 7. The lengths of the longest bridges in the United States are shown. Which statement is supported by the data? A. If the lengths of the bridges were distributed equally among all five bridges, each would measure 95,250 feet in length. B. There is no bridge length that occurs more often than another. C. The lengths of the bridges have a range of 82,000 feet. D. The majority of the bridges are greater than 97,000 feet in length.
Chapter 11 Review 8. GRIDDED RESPONSE A train is traveling 54.8 miles per hour. At this speed, how far will the train travel, in miles, in 3.2 hours?
Chapter 11 Review 8. GRIDDED RESPONSE A train is traveling 54.8 miles per hour. At this speed, how far will the train travel, in miles, in 3.2 hours? 54.8 mph · 3.2 hrs = 175.36 miles
Chapter 11 Review 9. Craig planted acre with vegetables. He divided the garden into sections that were of an acre. How many different sections will Craig have? F. G. H. I.
Chapter 11 Review 9. Craig planted acre with vegetables. He divided the garden into sections that were of an acre. How many different sections will Craig have? F. G. H. I. ÷ = Answer: F
Chapter 11 Review 10. SHORT RESPONSE The table shows students’ favorite track and field events. If 300 students were surveyed, how many would prefer long jump?
Chapter 11 Review 10. SHORT RESPONSE The table shows students’ favorite track and field events. If 300 students were surveyed, how many would prefer long jump? 26% of 300 is 78 Calculator 26, 2nd, %, 300, =
Chapter 11 Review 11. The weight of a small dog is about 10 times the weight of a guinea pig shown. What is the estimated weight of the small dog? A. 0.2 lb B. 10 lb C. 20 lb D. 200 lb
Chapter 11 Review 11. The weight of a small dog is about 10 times the weight of a guinea pig shown. What is the estimated weight of the small dog? A. 0.2 lb B. 10 lb C. 20 lb D. 200 lb 10 times 2 lbs = 20 lbs Answer: C
Chapter 11 Review 12. The table shows the number of goals scored by Major League Soccer players in a recent year. Which measure of center best represents the data? F. outlier G. mode H. range I. mean
Chapter 11 Review 12. The table shows the number of goals scored by Major League Soccer players in a recent year. Which measure of center best represents the data? F. outlier G. mode H. range I. mean Range and outliers arenot a measure of center. Since there are no outliers, the mean would be the best. Answer: I
Chapter 11 Review 13. What is the solution to the equation 1.7t = 8.5? A. 5 B. 6.8 C. 10.2 D. 14.45
Chapter 11 Review 13. What is the solution to the equation 1.7t = 8.5? A. 5 B. 6.8 C. 10.2 D. 14.45 1.7t = 8.5 = t = 5 Answer: A
Chapter 11 Review 14. EXTENDED RESPONSE Kamilahis researching the number of channels available from different cable and satellite companies. The table shows the results. Part A Find the mean, median, mode,and range. Part B How does the outlier affect the values you found for Part A?
Chapter 11 Review 14. EXTENDED RESPONSE Kamilahis researching the number of channels available from different cable and satellite companies. The table shows the results. Part A Find the mean, median, mode,and range. Mean: 265+70+85+120+135=675÷5=135
Chapter 11 Review 14. EXTENDED RESPONSE Kamilahis researching the number of channels available from different cable and satellite companies. The table shows the results. Part A Find the mean, median, mode,and range. Mean: 265+70+85+120+135=675÷5=135 Median: 70, 85, 120, 135, 265
Chapter 11 Review 14. EXTENDED RESPONSE Kamilahis researching the number of channels available from different cable and satellite companies. The table shows the results. Part A Find the mean, median, mode,and range. Mean: 265+70+85+120+135=675÷5=135 Median: 70, 85, 120, 135, 265 Mode: no mode
Chapter 11 Review 14. EXTENDED RESPONSE Kamilahis researching the number of channels available from different cable and satellite companies. The table shows the results. Part A Find the mean, median, mode,and range. Mean: 265+70+85+120+135=675÷5=135 Median: 70, 85, 120, 135, 265 Mode: no mode Range: 265 – 70 = 195
Chapter 11 Review 14. EXTENDED RESPONSE Kamilahis researching the number of channels available from different cable and satellite companies. The table shows the results. Part B How does the outlier affect the values you found for Part A?
Chapter 11 Review 14. EXTENDED RESPONSE Kamilahis researching the number of channels available from different cable and satellite companies. The table shows the results. Part B How does the outlier affect the values you found for Part A? The number 265 makes the measures of center much higher. It also makes the range much larger.
Chapter 11 Review Agenda Notes Homework– Homework Practice OAA – CH11a Due Wednesday, April 23