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Momentum

Momentum. Total Recall. Total Recall. Remember what the term Inertia means?. Total Recall. Remember what the term Inertia means?. Total Recall. Remember what the term Inertia means? An object’s resistance to change it’s state of rest/motion. Total Recall.

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Momentum

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  1. Momentum

  2. Total Recall

  3. Total Recall • Remember what the term Inertia means?

  4. Total Recall • Remember what the term Inertia means?

  5. Total Recall • Remember what the term Inertia means? An object’s resistance to change it’s state of rest/motion

  6. Total Recall • Remember what the term Inertia means? An object’s resistance to change it’s state of rest / motion Let’s just look at the motion part of that

  7. Total Recall • Remember what the term Inertia means? An object’s resistance to change it’s state of rest / motion Let’s just look at the motion part of that Also recall that inertia is measured in terms of mass….so….the more mass an object has the more inertia it has

  8. Inertia in motion……..

  9. Inertia in motion…….. Is also called Momentum

  10. Momentum

  11. Momentum • P = mv

  12. Momentum • P = mv • Momentum = mass x velocity

  13. Momentum • P = mv • Momentum = mass x velocity • = kg x m/s

  14. Momentum • P = mv • Momentum = mass x velocity • kgm/s = kg x m/s no special units

  15. Momentum • P = mv • Momentum = mass x velocity • kgm/s = kg x m/s no special units • Uses letter P, not m since m stands for mass

  16. Momentum • P = mv • Momentum = mass x velocity • kgm/s = kg x m/s no special units • Uses letter P, not m since m stands for mass • A Vector quantity > has direction so + and – signs are used

  17. Ch…Ch..Ch…Changes

  18. Ch…Ch..Ch…Changes • We can change velocity

  19. Ch…Ch..Ch…Changes • We can change velocity • If we can change velocity, we can change momentum

  20. Ch…Ch..Ch…Changes • We can change velocity • If we can change velocity, we can change momentum • Mass will not change in our problems

  21. Ch…Ch..Ch…Changes • We can change velocity • If we can change velocity, we can change momentum • Mass will not change in our problems • So…..

  22. Change in Momentum Change in momentum = mass x change in velocity

  23. Change in Momentum Change in momentum = mass x change in velocity or

  24. Change in Momentum Change in momentum = mass x change in velocity or Δ P = m ΔV *And remember, V is really Vf - Vi

  25. For your consideration…

  26. For your consideration… • Momentum is directly proportional to the mass and the velocity

  27. For your consideration… • Momentum is directly proportional to the mass and the velocity • If mass increases by a factor of 2, the momentum increases by a factor of 2

  28. For your consideration… • Momentum is directly proportional to the mass and the velocity • If mass increases by a factor of 2, the momentum increases by a factor of 2 • If velocity increases by a factor of 3, the momentum increases by a factor of 3

  29. Example Problems

  30. Example Problems

  31. Example Problems A 14 kg remote controlled car is traveling at 3 m/s. What is it’s momentum?

  32. Example Problems A 14 kg remote controlled car is traveling at 3 m/s. What is it’s momentum? Mass = 14 kg

  33. Example Problems A 14 kg remote controlled car is traveling at 3 m/s. What is it’s momentum? Mass = 14 kg Velocity = 3 m/s

  34. Example Problems A 14 kg remote controlled car is traveling at 3 m/s. What is it’s momentum? Mass = 14 kg Velocity = 3 m/s P=mv

  35. Example Problems A 14 kg remote controlled car is traveling at 3 m/s. What is it’s momentum? Mass = 14 kg Velocity = 3 m/s P=mv = 14 x 3

  36. Example Problems A 14 kg remote controlled car is traveling at 3 m/s. What is it’s momentum? Mass = 14 kg Velocity = 3 m/s P=mv = 14 x 3 = 42 kgm/s

  37. Example Problems A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum?

  38. Example Problems A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? M=4890 g

  39. Example Problems A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? M=4890 g = 4.89 kg

  40. Example Problems A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? M=4890 g = 4.89 kg Vi=1.2 m/s

  41. Example Problems A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? M=4890 g = 4.89 kg Vi=1.2 m/s Vf=5.4 m/s

  42. Example Problems • A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? • M=4890 g = 4.89 kg • Vi=1.2 m/s • Vf=5.4 m/s • P=m v

  43. Example Problems • A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? • M=4890 g = 4.89 kg • Vi=1.2 m/s • Vf=5.4 m/s • P=m v = m(Vf-Vi)

  44. Example Problems • A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? • M=4890 g = 4.89 kg • Vi=1.2 m/s • Vf=5.4 m/s • P=m v = m(Vf-Vi) = 4.89 ( 5.4 – 1.2)

  45. Example Problems • A 4890 g potato rolls down a hill. It started by being pushed at 1.2 m/s and reaches a velocity of 5.4 m/s at the bottom. What was the potato’s change in momentum? • M=4890 g = 4.89 kg • Vi=1.2 m/s • Vf=5.4 m/s • P=m v = m(Vf-Vi) = 4.89 ( 5.4 – 1.2) = 20.54 kgm/s

  46. More More More Here we go

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