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Boat Across The River

Boat Across The River. Done By: Khalid Salem Abdulrahman Khalid Majed Mohammed. Task 1:. Searched the web to find real life examples of vectors. We ended with modeling real life functions in space and resolving forces in Physics. Task 2:.

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Boat Across The River

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  1. Boat Across The River Done By: Khalid Salem Abdulrahman Khalid Majed Mohammed

  2. Task 1: • Searched the web to find real life examples of vectors. • We ended with modeling real life functions in space and resolving forces in Physics.

  3. Task 2: We founded the Direction and the magnitude of the new direction of the boat

  4. Horse 1= H → Hx= 300 cos(200) = -281.9 N → Hy=300sin200= -102.6 → H = <-281.9, -102.6> Task 3: Horse 2= T → Tx= 500 cos(150) = -422.01 N → Ty=500sin150= 250 N → T = <-422.01, 250> →→ H + T = <-281.9+-422.01, -102.6+250> = <-703.91, 147.4> → HT = (-703.91)2+(147.4)2=719.17 N

  5. Task 4: Let x = small/y = large The boat is part of delivering company, it can hold 1200 kg and its capacity is 7.20 cubic meter. The service handles two types of boxes: small, which weight is up to 20 kg and no more than 1200cm3, and large which 25 kg each and 1600 cm3 each. The delivery service charges 10Dhs for each small package, and 15 for each large package. a.) 20x+25y≤1200 b.) 12x+16y ≤7.2

  6. Scale: 10x10 And for C.

  7. d.)Write a function that represents the amount of money the delivery service will make on each boat hold. • fx=10x+15y • e.)Find the number of each type of the boxes that should be placed on a boat to maximize revenue. • f(0,0)=100+150=0 • f(0.6,0)=100.6+150= 6 • f(0,0.45)=100+150.45=6.75 • f.)What is the maximum revenue per boat? • 6.75

  8. Task 5: • Suppose that the force acting on the boat can be expressed by vector 45,24,110 where each measure in the ordered triple represents the force in Newton. What is the magnitude of the force?

  9. Task 6: • Workers are using a force of 200 Newton to push a cart up a ramp. The ramp is 6 feet long and is at 30° angle with the horizontal. How much work are the workers doing in the vertical direction?You may use sine ratio and formula W=F.d @=Angle Sin@=opp/hyp Sin(30)=6/hyp Hyp = 6/sin(30) Hyp=12ft W = FxD W=200 x 12 W= 2400J

  10. References and Wiki • www.mathwarehouse.com/vectors/ • http://galileoandeinstein.physics.virginia.edu/lectures/vectors.htm • http://boatacrossriver.wikispaces.com/

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