1 / 4

14. Between what symmetrical limits about the true population proportion of 0.08 do

14. Between what symmetrical limits about the true population proportion of 0.08 do (a) 90% of the sample proportions lie (n=64)? (b) 95% of the sample proportions lie (n=64)? (c) 99% of the sample proportions lie (n=64)?.

mostyn
Download Presentation

14. Between what symmetrical limits about the true population proportion of 0.08 do

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 14. Between what symmetrical limits about the true population proportion of 0.08 do (a) 90% of the sample proportions lie (n=64)? (b) 95% of the sample proportions lie (n=64)? (c) 99% of the sample proportions lie (n=64)?

  2. (a) 90% of the sample proportions lie (n=64)? = . 08 p = 64 n P(Z < z΄) = 0.5+ .90/2 = .95 = .9500 Z΄ = 1.645 90% Probability P(Z ≤ z’) hundredths Z΄ = 1.645 z’ .04 .05 Z=0 Z units tenths probability in shaded area 1.6 .9495 .9500 .9505

  3. (b) 95% of the sample proportions lie (n=64)? = . 08 p = 64 n P(Z < z΄) = 0.5+ .95/2 = .975 = .9750 Z΄ = 1.96 Z΄ 95% Probability P(Z ≤ z’) hundredths Z΄ = 1.96 z’ .06 Z=0 Z units tenths probability in shaded area 1.9 .9750

  4. (c) 99% of the sample proportions lie (n=64)? = . 08 p = 64 n P(Z < z΄) = 0.5+ .99/2 = .995 = .9950 Z΄ = 2.575 99% Probability P(Z ≤ z’) hundredths Z΄ = 2.575 z’ .07 .08 Z=0 Z units tenths probability in shaded area 2.5 .9949 .9950 .9951

More Related