1 / 30

Chapter 30

Chapter 30. Serway & Beichner. Force between two current carrying wires. Electric current The A mpere

nasia
Download Presentation

Chapter 30

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 30 Serway & Beichner

  2. Force between two current carrying wires

  3. Electric current The Ampere The ampere is that constant current which, if maintained in two straight parallel conductors of infinite length, of negligible circular cross-section, and placed 1 m apart in vacuum, would produce a force between them equal to 2 × 10-7 Newton per meter of length.

  4. Fig 30-8, p.932

  5. Fig 30-9c, p.933

  6. Fig 30-1, p.927

  7. See Ex. 30.1 Fig 30-3, p.929

  8. @ z = 0 z >> R See Ex. 30.3 Fig 30-7, p.931

  9. Fig 30-17, p.938

  10. for r > R Application of Ampère’s Law for r < R Fig 30-12, p.935

  11. Field inside Solenoid Fig 30-19, p.939

  12. start 9/13/04

  13. Magnetic Flux B = B•dA = BAcos Fig P30-20, p.940

  14. Ampère’s Law One More Time Ampere’s law states that the line integral of B.ds around any closed loop equals moI where I is the total steady current passing through anysurface bounded by the closed loop.

  15. Apply Ampère’s Law to either the, white or gray surfaces, both of which are bounded by the red loop. This leads to: Assume that I is constant. Now introduce a capacitor to interrupt the the circuit. If our power supply is strong enough to keep I constant, the gray surface will give B = 0! What’s wrong?

  16. E = E•dA = Q/o Electric flux will change in time corresponding to an effective current called the Displacement Current If the power supply can keep the current constant, the cap. will be charged: +Q/-Q on left/right plate. This establishesan E-field between the two plates.

  17. Consider to different surfaces

  18. Orbital Motion of the Electron in an Atom Fig 30-27, p.945

  19. Magnetic Moments due to Spin of electron, neutron and proton Fig 30-28, p.946

  20. 10-24 J/T Magnetic Moments  10-26 J/T Table 30-1, p.946

  21. Polarization Generated Field points in the opposite direction

  22. Table 30-2, p.948

  23. Paramagnetism Generated field adds to applied field Atomic currents

  24. Diamagnetism Generated field opposes applied field

  25. Magnetic Domains

  26. The Earth as a big magnet

More Related