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a. Ln[A]= -Kt +Ln[A] o Ln[61.5]= -K(480) + Ln[100] Ln[.615]= -K(480) K=0.00101

#39 A first-order reaction is 38.5% complete in 480. s. a. Calculate the rate constant. b. What is the value of the half-life? c. How long will it take for the reaction to go to 25%, 75%, and 95% completion?. a. Ln[A]= -Kt +Ln[A] o Ln[61.5]= -K(480) + Ln[100] Ln[.615]= -K(480) K=0.00101.

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a. Ln[A]= -Kt +Ln[A] o Ln[61.5]= -K(480) + Ln[100] Ln[.615]= -K(480) K=0.00101

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  1. #39A first-order reaction is 38.5% complete in 480. s.a. Calculate the rate constant.b. What is the value of the half-life?c. How long will it take for the reaction to go to 25%, 75%, and 95% completion?

  2. a.Ln[A]= -Kt +Ln[A]oLn[61.5]= -K(480) + Ln[100]Ln[.615]= -K(480)K=0.00101

  3. b. Ln[1/2]=-Kt +Ln[A]0Ln[50]= (-0.00101)t + Ln[100]t=686 s

  4. c. Ln[A]= -Kt +Ln[A]oLn[75]= (-0.00101)t + Ln[100]t= 280 sLn[25]= (-0.00101)t + Ln[100]t= 1400 sLn[5]= (-0.00101)t + Ln[100]t= 3000 s

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