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HCl agust,heima,...Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp (JMS paper)

HCl agust,heima,...Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp (JMS paper) agust,www, ....Sept10/PPT-141210ak.ppt agust,heima,...Sept10/HCl(3+1)j3Sigma(0) Calc-141210ak.pxp (R-C spectrum)

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HCl agust,heima,...Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp (JMS paper)

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  1. HCl agust,heima,...Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp (JMS paper) agust,www, ....Sept10/PPT-141210ak.ppt agust,heima,...Sept10/HCl(3+1)j3Sigma(0) Calc-141210ak.pxp (R-C spectrum) agust,heima,...Sept10/XLS-141210ak.xlsagust,heima,...Sept10/XLS-151210ak.xlsagust,heima,...Sept10/XLS-161210ak.xls agust,heima,...Sept10/22320_22356-161210ak.pxp (new R-T spectrum) agust, heima,...Sept10/J3S_V1S21-171210ak.pxp (new R-T spectrum) agust,heima,...Sept10/aHCl(3+1)j3S(0)Calc-201210ak.pxpagust,heima,...Sept10/XLS-201210ak.xls agust,heima,...Sept10/Look for J7-201210.pxp

  2. JMS, 228,143,(2004)-assignment KM´s assignment REMPI-current agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp, Lay: 5, Gr:2_1

  3. JMS, 228,143,(2004)-assignment 9 6 8 4 3 2 1 0 KM´s assignment 5 7 agust,heima,...Sept10/HCl(3+1)j3Sigma(0) Calc-141210ak.pxp (R-C spectrum), Lay:2, Gr:1

  4. NB!: KM´s (REMPI-TOF; R-T) spectrum is a lot colder than the JMS (20014)-REMPI- current (R-C) spectrum

  5. Now lets try • Derive Energy level values both from R-T and R-C spectra using • KM´s assignment and check shifts. • 2) Insert Wangs and Longs´newest spectra uncluding “newly observed “ • peaks for comparison. from KM: Slide 7 Slide 6 agust,heima,...Sept10/XLS-151210ak.xls

  6. From REMPI-TOF (KM): E(J´) Coefficient values ± one standard deviation K0=C = 89281 ± 3.56 K1=B´ = 9.7179 ± 0.229 K2=D´ = 0.0026284 ± 0.0026 J´=9 J´=7 J´=6 J´(J´+1) agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp, Lay: 7, Gr:11

  7. From REMPI-TOF (KM): DE J´,J´-1 23.78 4.8436663 cm-1 agust,heima,...Sept10/XLS-151210ak.xls = 19.497 J´ = 2B´J´=> B´= 9.7485 cm-1 J´ agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp, Lay: 6, Gr:9

  8. Now let´s look at the latest data for V, v´=21 from Long and Wang: I will wait for Longs analysis and summaries of mass spectra vs REMPI peaks

  9. Let´s look at the REMPI-current data Let´s look at energy levels or the V, v´=21 state: Is there a shift of levels to be found?

  10. V,v´=21, J´=6 i=35 i=37 H+ agust,heima,...Sept10/22320_22356-161210ak.pxp, Lay:0, Gr:1

  11. agust,heima,...Sept10/XLS-161210ak.xls

  12. From REMPI-TOF (VHW&JL): DE J´,J´-1 24.95 cm-1 agust,heima,...Sept10/XLS-151210ak.xls = 6.8778 J´ = 2B´J´=> B´= 3.4389 cm-1 J´ agust,heima,...Sept10/22320_22356-161210ak.pxp, Lay:1, Gr:2

  13. (W&L´s observation for J´=6 (V)(?): n(J’=6;V)-n(J´=6,j)=90.8 cm-1) KM´s prediction, assuming n(J’=6;V)-n(J´=6,j)=64cm-1 NB!: According to KM (211210) the peak at 22334.27 89337.08 is a S line peak for V!! The broad peaks However might be V,v´=21, J´=6 agust,heima,...Sept10/22320_22356-161210ak.pxp, Lay:0, Gr:1

  14. agust,heima,...Sept10/XLS-161210ak.xls

  15. W12 dervid from J´=6 NB! Not needed in calculation of W12 (see below) (E2 (6) = 89774.7 ) ? 24.95cm-1 J´(V, v´=21) = 6 E20(6) = 89749.7 89719.2 cm-1 4.84 cm-1 89688.7 = E10(6) J´(j, v´=0) = 6 89683.9 = E1 (6) agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp, Lay: 8, Gr:12

  16. W12 derived from J´=7 : DE J´,J´-1 V,v´=21 state data This is slightly underestimated value This is largely overestimated value J´ agust,heima,...Sept10/22320_22356-171210ak.pxp, Lay:1, Gr:2

  17. The large difference in W12 obtained for J´= 6 and 7 suggests that the Line assignment for j<-<-X is wrong(?). Let´s check other possibilities. 1) OLD assignment: NO evaluation method is no good!

  18. Old assignment 20.707 3.27 j,v´=0 state data

  19. OLD assignment gives largest gap for J´=7 <->J´=8 whereas KM´s assignment gives largest gap for J´=6 <->J´=7 Is it possible to find largest gap for J´=5 <->J´=6? That would fit with the V, v´= 21 gap / shifts! ATH! Larger Cl+/HCl+ ratios according to KM = j state peaks Large gap: 6<->7 7<->8 5<->6 5<->6 6<->7 6<->7 KM: 9 6 8 5 7 4 3 2 1 0 OLD: 10 11 9 7 8 6 5 4 3 2 1 AK(1) 9 5 7 8 6 4 3 2 1 0 AK(2) 9 5 8 7 6 4 3 2 1 0 AK(3) 8 - 6 - 5 7 4 3 2 1 0 AK(4) 9 6 6/8 5 5 7 4 3 2 1 0 NO! 9 10 J(1);S i=37 overlap

  20. AK(1) assignment: NO! agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp, Lay: 10, Gr:14

  21. Could be 37 peak from V, v´=21 J, v´=0 H37Cl+ 35Cl+ H35Cl+ H+ 1hv agust, heima,...Sept10/J3S_V1S21-171210ak.pxp; Lay: 2, Gr: 1

  22. AK(2) assignment (see slide 19): NO! agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp, Lay: 11 Gr:15

  23. Energy levels (E(J´): J(0+)-state <= KM V,v´=21 state 13.018 cm-1 J´=7 89844.13475 J´=7 89799.8784 89828.476 J´=6 J´=6 agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-201210ak.pxp, Lay: 12, Gr:16 and .....Sept10/XLS-201210ak.xls

  24. AK(3) assignment (see slide 19): agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-201210ak.pxp, Lay: 13 Gr:17

  25. J(0+)-state <= AK(3) 12.298 cm-1 V,v´=21 state J´=7 J´=6 agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-201210ak.pxp, Lay: 12, Gr:16 and .....Sept10/XLS-201210ak.xls

  26. Now it is possible to predict the position of the J´=9 band agust,heima.....Sept10/XLS-201210ak.xls

  27. J(0+)-state <= AK(3) Fits nicely J´=7 J´=6 agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-201210ak.pxp, Lay: 12, Gr:16 and .....Sept10/XLS-201210ak.xls

  28. 5 6 7 8 9 5 9 7 6 8 4.02 This could be V, v´=21, J´=7(?) agust,heima,...Sept10/Look for J7-201210.pxp

  29. See also figs in KM´s manuscript and my comments there. It is worth performing some isotopomer calculations NB! According to Longs estimate (agust,heima,..../Sept10/V state V21q energy diference between H35Cl and H37Cl-141210jl-201210ak.xls) The isotope separation for J´= could be < 5. Now let´s check where exactly j(1), S serie peak is to be found.

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