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Heat of reaction equations

Heat of reaction equations. Using simultaneous equations. Simultaneous equations. GIVEN: Δ H A + B = C -50 D + E = F +24 F + C = H ???. Simultaneous equations. GIVEN: Δ H A + B = C -50 D + E = F +24 F + C = A+ B + C + D ???. Simultaneous equations.

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Heat of reaction equations

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  1. Heat of reaction equations Using simultaneous equations

  2. Simultaneous equations GIVEN: ΔH A + B = C -50 D + E = F +24 F + C = H ???

  3. Simultaneous equations GIVEN: ΔH A + B = C -50 D + E = F +24 F + C = A+ B + C + D ???

  4. Simultaneous equations GIVEN: ΔH A + B = C -50 D + E = F +24 A+ B + E + D= H -26

  5. INTERPRETING DATA • In any reaction, the heat taken in or given out is determined by the direction of the reaction. • Always work left to right ΔH A + B = C - 50

  6. INTERPRETING DATA • In any reaction, the heat taken in or given out is determined by the direction of the reaction. • Always work left to right ΔH A + B = C - 50 C = A + B ......

  7. INTERPRETING DATA • In any reaction, the heat taken in or given out is determined by the direction of the reaction. • Always work left to right ΔH A + B = C - 50 C = A + B +50

  8. INTERPRETING DATA • In any reaction, the heat taken in or given out is determined by the direction of the reaction. • Always work left to right ΔH A + B = C - 50 C = A + B +50 • If the direction of the reaction is reversed, the sign of the energy is changed (- to + or + to –)

  9. Using this to solve an unknown reaction • Q6(e) The combustion of Butene C4H8 is described by the following balanced equation. C4H8 + 6O2 4CO2 + 4H2O ΔH = –2710 kJ mol–1 The standard heats of formation of water and carbon dioxide are –286 and –394 kJ mol–1, respectively. Calculate the heat of formation of C4H8

  10. What have we been told?? • Q6(e) The combustion of Butene C4H8 is described by the following balanced equation. • C4H8+ 6O2 4CO2 + 4H2O ΔH = –2710 kJ mol–1 This is the energy given out when butene is burned in oxygen

  11. What have we been told?? • Q6(e) The combustion of one of Butene C4H8 is described by the following balanced equation. C4H8 + 6O2 4CO2 + 4H2O ΔH = –2710 kJ mol–1 The standard heats of formation of water and carbon dioxide are –286 and –394 kJ mol–1, respectively. Calculate the heat of formation of C4H8

  12. What have we been told?? The standard heats of formation of water and carbon dioxide are –286 and –394 kJ mol–1, respectively. ΔH = kJ mol–1 H2 + ½O2 H2O -286 C + O2 CO2 -394

  13. What do we need to know? 4C + 4H2C4H8 ΔH = ??? Using all the given info one has to manipulate the given formulas to leave the needed one. The question seeks to answer if the formation of butene is exothermic or endothermic

  14. What’s next? Write down all the info you have. ΔH = kJ mol–1 H2 + ½O2 H2O -286 C + O2 CO2 -394 C4H8 + 6O2 4CO2 + 4H2O –2710

  15. What’s next? Write down all the info you have. ΔH = kJ mol–1 H2 + ½O2 H2O -286 C + O2 CO2 -394 C4H8 + 6O2 4CO2 + 4H2O –2710 4C + 4H2C4H8 ΔH = ???

  16. What’s next? ΔH = kJ mol–1 H2 + ½O2 H2O -286 C + O2 CO2 -394 C4H8 + 6O2 4CO2 + 4H2O –2710 4C + 4H2C4H8 ΔH = ???

  17. What’s next? ΔH = kJ mol–1 H2 + ½O2 H2O -286 C + O2 CO2 -394 C4H8 + 6O2 4CO2 + 4H2O –2710 4CO2 + 4H2O C4H8 + 6O22710 reverse 4C + 4H2C4H8 ΔH = ???

  18. What’s next? ΔH = kJ mol–1 H2 + ½O2 H2O -286 C + O2 CO2 -394 C4H8 + 6O2 4CO2 + 4H2O –2710 4CO2 + 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 x4 4C + 4H2C4H8 ΔH = ???

  19. What’s next? ΔH = kJ mol–1 H2 + ½O2 H2O -286 C + O2 CO2 -394 C4H8 + 6O2 4CO2 + 4H2O –2710 4CO2 + 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144 x4 4C + 4H2C4H8 ΔH = ???

  20. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2 + 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144

  21. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144

  22. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144

  23. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144

  24. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144

  25. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144

  26. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144

  27. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144 4C

  28. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144 4C

  29. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144 4C + 4H2

  30. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144 4C + 4H2

  31. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144 4C + 4H2 C4H8

  32. What’s next? 4C + 4H2C4H8 ΔH = ??? ΔH = kJ mol–1 4CO2+ 4H2O C4H8 + 6O22710 4C + 4O2 4CO2 -1576 4H2 + 2O2 4H2O -1144 4C + 4H2 C4H8 -10

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