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State null and alternative hypotheses for different claims in hypothesis testing scenarios. Calculate margin of error, set up a confidence interval, and make the decision whether to reject or fail to reject the null hypothesis. Determine the implications of the test results for each claim.
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1. State the null and alternative hypotheses used to test the following claims: A school publicises that the percentage of its students who are involved in at least one extracurricular activity is 61%. (i) The percentage of students involved in at least one extracurricular activity is 61%. H0: The percentage of students involved in at least one extracurricular activity is not 61%. H1:
1. State the null and alternative hypotheses used to test the following claims: A car garage announces that the mean time for a wheel change is less than 15 minutes. (ii) The mean time for a wheel change is less than 15 minutes. H0: H1: The mean time for a wheel change is not lessthan 15 minutes.
1. State the null and alternative hypotheses used to test the following claims: A company advertises that the mean life of its products is more than eight years. (iii) The mean life of the products is more than 8 years. H0: H1: The mean life of the productsis not more than 8 years.
1. State the null and alternative hypotheses used to test the following claims: A drug company announces that a new vaccine is 10% more effective than its predecessor. (iv) The new vaccine is 10% more effective than the previous. H0: H1: The new vaccineis not 10% more effective than the previous.
1. State the null and alternative hypotheses used to test the following claims: A skincare company advertise that 35% of people surveyed thought that their product reduced skin oiliness. (v) The percentage of people who thought the product reduced skin oiliness is 35%. H0: The percentage of people who thought the product reduced skin oiliness is not 35%. H1:
2. An advertisement states that 8 out of 10 cats prefer Catty Cat cat food. To test this claim, a researcher carried out an experiment using 150 cats and found that 75 cats preferred Catty Cat. State the null and alternative hypotheses. (i) The proportion of cats who prefer Catty Cat is 0·8 H0: H1: The proportion of cats whopreferCatty Cat is not 0·8.
2. An advertisement states that 8 out of 10 cats prefer Catty Cat cat food. To test this claim, a researcher carried out an experiment using 150 cats and found that 75 cats preferred Catty Cat. Calculate . (ii)
2. An advertisement states that 8 out of 10 cats prefer Catty Cat cat food. To test this claim, a researcher carried out an experiment using 150 cats and found that 75 cats preferred Catty Cat. Calculate the margin of error to two decimal places. (iii) Margin of error
2. An advertisement states that 8 out of 10 cats prefer Catty Cat cat food. To test this claim, a researcher carried out an experiment using 150 cats and found that 75 cats preferred Catty Cat. Set up the 95% confidence interval. (iv) 95% confidence interval = 0·5 − 0·08 < p < 0·5 + 0·08 = 0·42 < p < 0·58
2. An advertisement states that 8 out of 10 cats prefer Catty Cat cat food. To test this claim, a researcher carried out an experiment using 150 cats and found that 75 cats preferred Catty Cat. Decide whether to reject or fail to reject the null hypothesis. (v) H0 states the proportion is 0·8 which does not fall within the confidence interval so we reject H0.
2. An advertisement states that 8 out of 10 cats prefer Catty Cat cat food. To test this claim, a researcher carried out an experiment using 150 cats and found that 75 cats preferred Catty Cat. Decide whether to reject or fail to reject the null hypothesis. (v) H0 states the proportion is 0·8 which does not fall within the confidence interval so we reject H0. What does this mean in relation to the claim? (vi) It appears the claim that 8 out of 10 cats prefer Catty Cat food is untrue.
3. A hotel chain claims that 35% of its online reviews are positive. A sample of 200 reviews shows that 120 are positive. State the null and alternative hypotheses. (i) The percentage of positive reviews is 35%. H0: H1: The percentage of positive reviewsis not 35%.
3. A hotel chain claims that 35% of its online reviews are positive. A sample of 200 reviews shows that 120 are positive. Calculate . (ii)
3. A hotel chain claims that 35% of its online reviews are positive. A sample of 200 reviews shows that 120 are positive. Calculate the margin of error to two decimal places. (iii) Margin of error
3. A hotel chain claims that 35% of its online reviews are positive. A sample of 200 reviews shows that 120 are positive. Set up the 95% confidence interval. (iv) 0·6 − 0·07 < p < 0·6 + 0·07 0·53 < p < 0·67
3. A hotel chain claims that 35% of its online reviews are positive. A sample of 200 reviews shows that 120 are positive. Decide whether to reject or fail to reject the null hypothesis. (v) We reject the null hypothesis because 35% = 0·35 which does not fall within the confidence interval. What does this mean in relation to the claim? (vi) This means the claim that 35% of online reviews are positive is untrue. In fact it appears that the number of positive reviews are actually higher than the company claims.
4. An opinion poll of 1,000 voters is carried out prior to an election. 25% of those polled said they would vote for the Left Party. Left Party management believe they have 35% support. Set up the 95% confidence interval. (i) Left party receive 35% of the votes in the election. H0: H1: Left party do not receive 35% of the votes in the election. = 0·25 (given in question)
4. An opinion poll of 1,000 voters is carried out prior to an election. 25% of those polled said they would vote for the Left Party. Left Party management believe they have 35% support. Set up the 95% confidence interval. (i) Margin of error 0·25 − 0·03 < p < 0·25 + 0·03 0·22 < p < 0·28
4. An opinion poll of 1,000 voters is carried out prior to an election. 25% of those polled said they would vote for the Left Party. Left Party management believe they have 35% support. Decide whether to reject or fail to reject the null hypothesis, using a 5% level of significance. (ii) We reject the null hypothesis as 0·35 does not fall within the confidence interval. What does this mean in relation to the claim? (iii) This means that the claim is incorrect.
5. Evie rolled a die 360 times and got 72 fives. She suspects that the die is biased and carries out a hypothesis test to check. What proportion of fives would Evie expect if the die was unbiased? (i) should be 5’s = (Probability of rolling a 5)
5. Evie rolled a die 360 times and got 72 fives. She suspects that the die is biased and carries out a hypothesis test to check. What is the null hypothesis? (ii) H0: The die is unbiased [Die is always assumed to be fair] What is the alternative hypothesis? (iii) H1: The die is biased
5. Evie rolled a die 360 times and got 72 fives. She suspects that the die is biased and carries out a hypothesis test to check. Use a hypothesis test at the 95% confidence level to determine if the die is biased. (iv) Margin of error 0·2 − 0·05 < p < 0·2 + 0·05 0·15 < p < 0·25 We fail to reject the null hypothesis since falls within the confidence interval. This implies the die is unbiased (fair).
6. A community sports organisation claims that it has equal numbers of males and females. A local councillor wanted to investigate this claim. He took a sample of 80 members and found that 65 of them were male. Determine whether the sports organisation’s claim is true, using 5% level of significance. H0: The percentage of members that are male is 50% (0·5). H1: The percentage of members that are male is not 50%. 0·81 − 0·11 < p < 0·81 + 0·11 0.7 < p < 0.92
6. A community sports organisation claims that it has equal numbers of males and females. A local councillor wanted to investigate this claim. He took a sample of 80 members and found that 65 of them were male. Determine whether the sports organisation’s claim is true, using 5% level of significance. We reject the null hypothesis as 0·5 does not fall within the confidence interval. Therefore, the claim that the organisation has equal numbers of males and females is untrue.
7. The Irish Tourist Board claimed that 65% of the tourists who visited Ireland last year were return visitors. The Department of Transport, Tourism and Sport wanted to test this claim. They asked a random sample of 800 tourists if they had been to Ireland before. 300 responded that they had. Using a 95% confidence interval, decide whether to reject or fail to reject the null hypothesis. (i) The percentage of first time visitors to Ireland is 65% (0·65) H0: H1: The percentage of first time visitors to Ireland is not 65%.
7. The Irish Tourist Board claimed that 65% of the tourists who visited Ireland last year were return visitors. The Department of Transport, Tourism and Sport wanted to test this claim. They asked a random sample of 800 tourists if they had been to Ireland before. 300 responded that they had. Using a 95% confidence interval, decide whether to reject or fail to reject the null hypothesis. (i) 0·38 − 0·04 < p < 0·38 + 0·04 0·34 < p < 0·42 We reject the null hypothesis as 0·65 does not fall in the confidence interval.
7. The Irish Tourist Board claimed that 65% of the tourists who visited Ireland last year were return visitors. The Department of Transport, Tourism and Sport wanted to test this claim. They asked a random sample of 800 tourists if they had been to Ireland before. 300 responded that they had. What does this mean in relation to the Irish Tourist Board’s claim? (ii) This means the claim is untrue. The percentage of first time visitors is lower than 65%.
8. A popular mobile phone provider claims that 70% of their customers are satisfied with the service provided by them. A consumer agency decides to investigate the claim. They survey 900 of the mobile company’s customers and find that 650 people said they were satisfied. Test the company’s claim using a 5% level of significance. As a result of your findings, what advice would you give to the mobile company? H0: The percentage of satisfied customers is 70% (0·7) H1: The percentage of satisfied customers is not 70%.
8. A popular mobile phone provider claims that 70% of their customers are satisfied with the service provided by them. A consumer agency decides to investigate the claim. They survey 900 of the mobile company’s customers and find that 650 people said they were satisfied. Test the company’s claim using a 5% level of significance. As a result of your findings, what advice would you give to the mobile company? 0·72 − 0·03 < p < 0·72 + 0·03 0·69 < p < 0·75 We fail to reject the null hypothesis as 0·7 falls within the confidence interval.It appears the company’s satisfaction rate is higher than claimed. Advice to the company: They should continue to provide the services they do.
9. A company manufacturing a new type of chocolate bar claims that 85% of the people who tried their product would recommend it to a friend. An independent study of 625 people who tried the bar, found that only 125 would recommend it. Use a 95% confidence interval to investigate whether the company’s claim is true. H0: The percentage of people that would recommend the new chocolate bar to a friend is 85%. H1: The percentage of people that would recommend the new chocolate bar to a friend is not 85%.
9. A company manufacturing a new type of chocolate bar claims that 85% of the people who tried their product would recommend it to a friend. An independent study of 625 people who tried the bar, found that only 125 would recommend it. Use a 95% confidence interval to investigate whether the company’s claim is true. 0·2 − 0·04 < p < 0·2 + 0·04 0·16 < p < 0·24 We reject the null hypothesis as 0·85 falls outside the confidence interval. Therefore, the claim is untrue.
10. The Union of Secondary Students of Ireland claims that 65% of Leaving Cert students spend more than three hours a night on study or homework. The principal of a school wants to investigate this claim. She surveys the 200 Leaving Cert students in her school and finds that 85 of them report spending more than three hours on study or homework. Using a 95% confidence interval, determine whether that principal is likely to accept the claim of the Students’ Union. H0: The percentage of Leaving Certificate students studying more than 3 hours a night is 65% (0·65). H1: The percentage of Leaving Certificate students studying more than 3 hours a night is not 65% (0·65).
10. The Union of Secondary Students of Ireland claims that 65% of Leaving Cert students spend more than three hours a night on study or homework. The principal of a school wants to investigate this claim. She surveys the 200 Leaving Cert students in her school and finds that 85 of them report spending more than three hours on study or homework. Using a 95% confidence interval, determine whether that principal is likely to accept the claim of the Students’ Union. 0·43 − 0·07 < p < 0·43 + 0·07 0·36 < p < 0·5 The null hypothesis is rejected as 0·65 does not fall within the confidence interval. Therefore, the principal is unlikely to accept the claim.