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Chapter 8

Chapter 8. Problem 8-6. Problem 8-15. µ=60 σ =12. 24. 96. 72. 48. Problem 8-15(contd.). .2734. .2266. 63. Problem 8-15(contd.). m. =. 60. x. s. =. 4. x. -. m. -. x. 56. 60. =. =. =. x. z. 1. 0. s. 4. x. 56. Problems 8-16.

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Chapter 8

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  1. Chapter 8

  2. Problem 8-6

  3. Problem 8-15 µ=60 σ=12 24 96 72 48

  4. Problem 8-15(contd.) .2734 .2266 63

  5. Problem 8-15(contd.) m = 60 x s = 4 x - m - x 56 60 = = = x z 1 . 0 s 4 x 56

  6. Problems 8-16 Since n=40,the sampling distribution of means will approximate a normal distribution .4943 .3962 .3962 74 76 77

  7. Problem 8-16(Contd.) < = - = a . p ( x 74 ) . 5000 . 3962 . 1038 - m - x 74 75 = = = - x z 1 . 26 5 x 40 < < = + = b . p ( 74 x 76 ) . 3962 . 3962 . 7924 < < = - = c . p ( 76 x 77 ) . 4943 . 3962 . 0981 - m - x 77 75 = = = x z 2 . 53 5 x 40 > = - = d . p ( x 77 ) . 5000 . 4943 . 0057

  8. Problem 8-17 1950

  9. Problem 8-18 > = + = b . p ( x 320 ) . 2852 . 5000 . 7852 - m x - 320 330 = x = = - z . 79 80 = = = 80 a . 12 . 649 minutes x x n 40 40 .2852 320

  10. Problem 8-18(Contd.) < < = + = c . p ( 320 x 350 ) . 2852 . 4429 . 7281 - m x - 350 330 x = = = z 1 . 58 80 40 .4429 .2852 320 350

  11. Problem 8-18 contd..

  12. Problem 8-34 • =110,000 • = 40,000/ 50 • = / n = 40,000/ 50 = 5657 • Normal distribution

  13. Problem 8-34 cont’d c. .1368 .3632 112,000 X =110,000 .35 Z P(X> 112,000)=.5000-.1368=.3632

  14. Problem 8-34 cont’d d. .4616 100,000 -1.77 Z P( X> 100,000)=.4616 +.5000=.9616

  15. Problem 8-34 cont’d e. .1368 .4616 100,000112,000 X -1.77 .35 Z P(100,000<X< 112,000)=.4616 + .1368 = .5984

  16. Problem 8-35 - m - x 25 . 1 24 . 8 = = = x z . 93 2 . 5 n 60 < = + = p ( x 25 . 1 ) . 5000 . 3238 . 8238 .3238 .93 Z

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