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The Ideal Gas Law

The Ideal Gas Law. PV=nRT P = Pressure V = Volume n = Number of Moles R = ideal gas constant T = temperature in Kelvin. R -The ideal gas constant. Depends on unit of pressure 0.0821 L . Atm / K . mol 62.4 L . mmHg / K . mol (torr is mm Hg) 8.31 L . kPa / K . mol.

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The Ideal Gas Law

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  1. The Ideal Gas Law PV=nRT • P = Pressure • V = Volume • n = Number of Moles • R = ideal gas constant • T = temperature in Kelvin

  2. R -The ideal gas constant • Depends on unit of pressure • 0.0821 L . Atm / K . mol • 62.4 L . mmHg / K . mol (torr is mm Hg) • 8.31 L . kPa / K . mol

  3. Ideal Gas Law example problem • Calculate the pressure of 1.65 g of helium gas at 16.0oC and occupying a volume of 3.25 L? • You will need g to moles and Celsius to Kelvin: • 1.65 g He 1 mole He • 4.0 g He = 0.413 mol He • K = oC + 273 ; 16. 0 + 273 = 289 K • For this problem you will need to pick an R value. For this problem I will choose to use the R value containing kPa. I picked it. You can’t do anything about it. So; just try and stop me. • Plug and Chug baby, get ‘R done. Do it. Come on I dare ya. • Get it - ‘R as in ideal gas constant

  4. Ideal Gas Law example problem • P x 3.25 L = 0.413 mol x 8.31 kPa . L x 289 K • mol . K • Do the algebra and solve; if you do it right, guess what? You get the answer right. Neat concept, huh? Maybe your mommy will give you a cookie. • = 305 kPa • Your turn • How many moles of gas are present in a sample of Argon at 58oC with a volume of 275 mL and a pressure of 0.987 atm.

  5. Ideal Gas Law example problem • Answer • 0.987 atm x 0.275 L = n x 0.0821 L . Atm x 331K • mol . K • Do the dew; oops, I mean the algebra and presto; the answer with the correct number of sig figs is.. • Do you know how to keep a so called chem student in suspense? • Do ya? • Do ya? • = 0.00999 mol Ar • Congrats - you can plug and chug. • Bye Bye now.

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