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14-5 Sum and Difference of Angles Formulas. The Formulas. Use the formula . Sum of angles. Evaluate each expression. Example 5-1a. Example:. Find the exact value of sin 75 . Multiply. Simplify. Answer:. Example 5-1b. Use the formula. Difference of angles.
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Use the formula . Sum of angles Evaluateeach expression. Example 5-1a Example: Find the exact value of sin 75.
Multiply. Simplify. Answer: Example 5-1b
Use the formula Difference of angles Evaluate eachexpression. Example 5-1c Another one: Find the exact value of cos (–75).
Multiply. Simplify. Answer: Example 5-1d
Answer: Answer: Example 5-1e More: Find the exact value of each expression. a. sin 105 b. cos (–120 )
Verify that is an identity. Answer: Original equation Difference ofangles formula Evaluate eachexpression. Simplify. Example 5-3a Another one:
Verify that is an identity. Original equation Answer: Difference ofangles formula Evaluate eachexpression. Simplify. Example 5-3b Another one:
Verify that each of the following is an identity. a. Answer: Example 5-3c Another one:
Find the value of if and is between Use the identity First find the value of Subtract. Example 6-1a Example:
Find the square root of each side. Since is in the first quadrant, cosine is positive. Thus, Example 6-1a
Double-angle formula Simplify. Now find Answer: The value of Example 6-1a Example:
Find the value of if and is between Double-angle formula Simplify. Answer: The value of cos 2 Example 6-1a Example:
Find the value of each expression if andis between a.b. Answer: Answer: Example 6-1b Some more:
Find is in the second quadrant. Since we must find first. Example 6-2a Example:
Simplify. Take the square root of each side. Since is in the second quadrant, Half-angle formula Example 6-2a
Simplify the radicand. Rationalize. Multiply. Example 6-2a
Answer: Since is between Thus, is positive and equals Example 6-2a
Find is in the fourth quadrant. Answer: Example 6-2b Yep, there is more:
Find the exact value of by using the half-angle formulas. Example 6-3a Example:
Simplify the radicand. Simplify the denominator. Answer: Example 6-3a
Find the exact value of by using the half-angle formulas. Example 6-3a Example:
Simplify the radicand. Simplify the denominator. Example 6-3a
Answer: Since is in the third quadrant,is negative. Thus, Example 6-3a
Find the exact value of each expression by using the half-angle formulas. a. b. Answer: Answer: Example 6-3b A few more:
Verify that is an identity. Original equation Distributive Property Simplify. Multiply. Example 6-4a Example: Answer:
Verify thatis an identity. Example 6-4b This could be the last one: Answer: