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More Applications of the Pumping Lemma

More Applications of the Pumping Lemma. The Pumping Lemma:. Given a infinite regular language. there exists an integer (critical length). for any string with length. we can write. with and. such that:. Non-regular languages.

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More Applications of the Pumping Lemma

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  1. More Applications ofthe Pumping Lemma Costas Busch - RPI

  2. The Pumping Lemma: • Given a infinite regular language • there exists an integer (critical length) • for any string with length • we can write • with and • such that: Costas Busch - RPI

  3. Non-regular languages Regular languages Costas Busch - RPI

  4. Theorem: The language is not regular Proof: Use the Pumping Lemma Costas Busch - RPI

  5. Assume for contradiction that is a regular language Since is infinite we can apply the Pumping Lemma Costas Busch - RPI

  6. Let be the critical length for Pick a string such that: and length We pick Costas Busch - RPI

  7. From the Pumping Lemma: we can write: with lengths: Thus: Costas Busch - RPI

  8. From the Pumping Lemma: Thus: Costas Busch - RPI

  9. From the Pumping Lemma: Thus: Costas Busch - RPI

  10. BUT: CONTRADICTION!!! Costas Busch - RPI

  11. Therefore: Our assumption that is a regular language is not true Conclusion: is not a regular language END OF PROOF Costas Busch - RPI

  12. Non-regular languages Regular languages Costas Busch - RPI

  13. Theorem: The language is not regular Proof: Use the Pumping Lemma Costas Busch - RPI

  14. Assume for contradiction that is a regular language Since is infinite we can apply the Pumping Lemma Costas Busch - RPI

  15. Let be the critical length of Pick a string such that: and length We pick Costas Busch - RPI

  16. From the Pumping Lemma: We can write With lengths Thus: Costas Busch - RPI

  17. From the Pumping Lemma: Thus: Costas Busch - RPI

  18. From the Pumping Lemma: Thus: Costas Busch - RPI

  19. BUT: CONTRADICTION!!! Costas Busch - RPI

  20. Therefore: Our assumption that is a regular language is not true Conclusion: is not a regular language END OF PROOF Costas Busch - RPI

  21. Non-regular languages Regular languages Costas Busch - RPI

  22. Theorem: The language is not regular Proof: Use the Pumping Lemma Costas Busch - RPI

  23. Assume for contradiction that is a regular language Since is infinite we can apply the Pumping Lemma Costas Busch - RPI

  24. Let be the critical length of Pick a string such that: length We pick Costas Busch - RPI

  25. From the Pumping Lemma: We can write With lengths Thus: Costas Busch - RPI

  26. From the Pumping Lemma: Thus: Costas Busch - RPI

  27. From the Pumping Lemma: Thus: Costas Busch - RPI

  28. Since: There must exist such that: Costas Busch - RPI

  29. However: for for any Costas Busch - RPI

  30. BUT: CONTRADICTION!!! Costas Busch - RPI

  31. Therefore: Our assumption that is a regular language is not true Conclusion: is not a regular language END OF PROOF Costas Busch - RPI

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