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Significance Testing

Significance Testing. Wed, March 24 th. Statistical Hypothesis Testing. Procedure that allows us to make decisions about pop parameters based on sample stats Example – mean aver salary of all workers = $28,985 (pop mean =  y)

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Significance Testing

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  1. Significance Testing Wed, March 24th

  2. Statistical Hypothesis Testing • Procedure that allows us to make decisions about pop parameters based on sample stats • Example – mean aver salary of all workers = $28,985 (pop mean = y) • Sample of 100 African Amer workers, mean salary = $24,100 (samp mean = ybar) • Is that a significant difference from the population? Or not enough of a difference to be meaningful?

  3. Steps of Hypothesis Tests • 1) State the Research & Null Hypotheses: • Research Hyp (H1): state what is expected & express in terms of pop parameter • Ex) y does not = $28,985 (Af Am salary doesn’t = pop salary; the groups differ) • Null Hyp (Ho): usually states there is no difference/effect (opposite of H1). • Ex) y = $28,985 (Af Am salary = pop salary)

  4. (cont.) • Note: Research Hyp (H1) also known as alternative hypothesis (Ha) • Null hypothesis is tested; we hope to reject it & find support for H1

  5. 1 & 2-tailed hypotheses • (Step 1 cont.) – possible to specify 1 or 2-tailed research hyp (H1) • 1-tailed is a directional hyp (expect  > some value or < some value) • 2-tailed is nondirectional (specify  is not equal to some value) • Use 1-tailed when you can rely on theory to know what to expect; 2-tailed if no prior expectation • Here, we could expect H1: y < $28,985 (1-tailed test that specifies a lower salary)

  6. Steps 2&3 : Select & Calculate the Appropriate Test Statistic • Here, a 1-sample z test to compare a sample mean to a known pop mean • Z = (Ybar – y) / ybar • Where ybar is std error and = y / sqrt N and ybar is sample mean; y is pop mean • Salary example: y = $28,985, y = $23,335ybar = $24,100 and N=100, so… • ybar =23,335 / sqrt(100) = 2,333.5

  7. Example (cont.) • Z = 24,100 – 28,985 / 2,333.5 = -2.09 • Step 4 – use unit normal table to make a probability decision • Look up z score of –2.09 (or 2.09) in column C (proportion beyond z), find .0183. • This is the prob of getting a sample result this extreme ($24,100) if the null hypothesis is true; called p value

  8. Step 4 (cont.): Decision • We define in advance what is sufficiently improbably to reject the null hypothesis • Find a cutoff point, called  (alpha) below which p must fall to reject null • Usually  = .05, .01, or .001 • Reject null when p <=  • Here, if choose  = .05, we reject null (p = .0183< .05  reject null)

  9. Interpretation • P = .0183 means there is only a 1.83% chance of finding a sample of 100 Afr Amer workers w/mean salary = 24,100 if there is really no difference from overall aver salary. (very unlikely) • Note: if p <  and we reject the null, we can say our findings are ‘statistically significant’; the groups differ significantly

  10. 2-tailed test interpretation • Our example used a 1-tailed test, if we’d made a 2-tailed H1 (y does not = $28,985), we need to adjust the p value • Look up z=-2.09 and find p=.0183, but need to multiple p x 2 if 2-tailed (.0183)x 2 = .0366 • P is still < , so still reject null

  11. Decision Errors • Possible to make 2 types of errors when deciding to reject/fail to reject Ho:

  12. Errors (cont.) • Type 1 error = probability of incorrectly rejecting a true Ho • Type 2 error = probability of failing to reject a false Ho • So when  = .05, we have a 5% chance of incorrectly rejecting Ho (Type 1) • Can be more conservative and use  = .01 (1% chance of Type 1), but then increases Type 2 chances…

  13. Lab 17 • Skip #5

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