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Sorting

Sorting. Sorting. Sorting is important! Things that would be much more difficult without sorting: finding a telephone number looking up a word in the dictionary finding a book in the library buying a cd renting a movie reading a book reading new email. How to sort?.

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Sorting

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  1. Sorting

  2. Sorting • Sorting is important! • Things that would be much more difficult without sorting: • finding a telephone number • looking up a word in the dictionary • finding a book in the library • buying a cd • renting a movie • reading a book • reading new email

  3. How to sort? • Think about sorting a hand of cards

  4. Comparison-based sorting • Sort by making comparisons • Ordering decision based on comparison of elements • Requires that elements are comparable • have a natural order • numerical • numbers • lexicographic (alphabetical) • characters • chronological • dates

  5. Insertion sort • Input: n elements in arbitrary order • For k = 2, …, n • compare elements in position k and position k-1 • if elements are unordered, swap them • compare elements in position k-1 and position k-2 • if elements are unordered, swap them • continue until you compare ordered elements or all elements have been swapped • once elements are sorted, they remain sorted relative to each other • Output: n elements in sorted order

  6. Insertion sort

  7. Worst case behavior • At each step k • compare element in position k with previous elements until first k elements are in sorted order • In the worst case, we compare each element with all of the previous elements • at step 2 we make 1 comparison • at step 3 we make 2 comparisons  • at step n we make n-1 comparisons • Worst case behavior occurs when the array is in reverse sorted order …

  8. Insertion sort – worst case

  9. Best case behavior • What if the elements are already sorted? • How many comparisons per element will be made by insertion sort?

  10. Insertion sort – best case

  11. (n-1) times Comparisons in insertion sort • Worst case • element k requires (k-1) comparisons • total number of comparisons: 0+1+2+ … + (n-1) = ½ (n)(n-1) = ½ (n2-n) • Best case • elements 2 through n each require one comparison • total number of comparisons: 1+1+1+ … + 1 = n-1

  12. The divide-and-conquer approach • Insertion sort uses an incremental approach • puts elements in correct place one at a time • We can design more efficient sorting algorithms using the divide-and-conquer approach: • Divide the problem into a number of subproblems • Conquer the subproblems by solving them recursively until the subproblems are small enough to solve directly • Merge the solutions for the subproblems into the solution for the original problem

  13. Mergesort • Divide-and-conquer sorting algorithm • Given a list of n elements in arbitrary order • Divide the list of n elements into two sub-lists of n/2 elements • Conquer each sub-list by sorting it recursively • Merge the solutions to all sub-lists into a single sorted list of n elements

  14. 27 10 12 20 27 10 12 20 10 12 20 27 10 27 12 20 10 12 20 27 Mergesort divide divide divide merge merge merge

  15. Merging • Idea: • suppose you have an unsorted deck of cards • you split the deck in half, give half to your friend to sort and sort the other half yourself • now you have two half-decks, each sorted • how do you combine them into a single sorted deck?

  16. Merging two sorted lists first list second list result of merge 10 27 12 20 10 10 27 12 20 10 12 10 27 12 20 10 12 20 10 27 12 20 10 12 20 27

  17. Comparisons in mergesort • Dividing a list of elements requires no comparisons • just compute midpoint • Merging two lists of size m requires at least m and at most 2m - 1 comparisons • one comparison at each step of the merge • elements in result list are not compared again • add at least one element to result at each step • Total number of comparisons is the sum of the number of comparisons made at each merge

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