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ELECTROCHEMISTRY Chap 20. Nernst Equation for a Complete Reaction. E cell = E + − E − = E cathode − E anode. Only valid when both ½-rxns written as reductions. Given: Cd ( s ) │ Cd(NO 3 ) 2 ( aq ); M A ║ FeCl 2 (aq); M C │ Fe ( s)
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ELECTROCHEMISTRY Chap 20
Nernst Equation for a Complete Reaction Ecell = E+ − E− = Ecathode − Eanode • Only valid when both ½-rxns written as reductions • Given: • Cd (s) │ Cd(NO3)2 (aq); MA ║ FeCl2 (aq); MC │ Fe (s) • [Cd2+] = 0.50 M; [Fe2+] = 0.10 M Ans = −0.058 V • (b) [Cd2+] = 0.010 M; [Fe2+] = 1.0 M; Ans = +0.021 V
In Class Exercise: Calculate the cell potential for: Cu │ CuCl2 (0.0200 M) ║ AgNO3 (0.0200 M) │ Ag Ans = +0.410 V Calculate the cell potential for: Pt │ UO22+ (0.0150 M); U4+ (0.200 M); H+ (0.0300 M ║ Fe2+ (0.0100 M); Fe3+ (0.0250 M) │ Pt Ans = +0.638 V UO22+ + 4H+ + 2e−→ U4+ + 2H2O;Eo= +0.334 V
Applications of Oxidation-Reduction Reactions • Batteries and Fuel Cells • Corrosion • Electrolysis
Batteries Fig 20.19 A 12 V automobile lead-acid battery Fig 20.19 Combining cells