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Introduction to Analysis of Algorithms. Introduction. What is Algorithm? a clearly specified set of simple instructions to be followed to solve a problem Takes a set of values, as input and produces a value, or set of values, as output May be specified In English
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Introduction • What is Algorithm? • a clearly specified set of simple instructions to be followed to solve a problem • Takes a set of values, as input and • produces a value, or set of values, as output • May be specified • In English • As a computer program • As a pseudo-code • Data structures • Methods of organizing data • Program = algorithms + data structures
What are the Algorithms? Algorithm: • Is any well-defined computational procedure that takes some value, or set of values, as input and produces some value, or set of values, as output. • It is a tool for solving a well-specified computational problem. • They are written in a pseudo code which can be implemented in the language of programmer’s choice.
Example: sorting numbers. Input: A sequence of n numbers {a3 , a1, a2,...,an } Output: A reordered sequence of the input {a1 , a2, a3,...,an } such that a1≤a2 ≤a3… ≤an . Input instance: {5, 2, 4, 1, 6, 3}. Output : {1, 2, 3, 4, 5, 6}. An instance of a problem consists of the input (satisfying whatever constraints are imposed in the problem statement) needed to compute a solution to the problem.
Example: sorting numbers. Sorting is a fundamental operation. Many algorithms existed for that purpose. The best algorithm to use depends on: The number of items to be sorted. possible restrictions on the item values kind of storage device to be used: main memory, disks, or tapes.
Correct and incorrect algorithms • Algorithm is correct if, for every input instance, it ends with the correct output. We say that a correct algorithm solves the given computational problem. • An incorrect algorithm might not end at all on some input instances, or it might end with an answer other than the desired one. • We shall be concerned only with correct algorithms.
Hard problems We can identify the Efficiency of an algorithm from its speed (how long does the algorithm take to produce the result). Some problems have unknown efficient solution. These problems are called NP-complete problems.
Big-O Notation • We use a shorthand mathematical notation to describe the efficiency of an algorithm relative to any parameter n as its “Order” or Big-O • We can say that the first algorithm is O(n) • We can say that the second algorithm is O(n2) • For any algorithm that has a function g(n) of the parameter n that describes its length of time to execute, we can say the algorithm is O(g(n)) • We only include the fastest growing term and ignore any multiplying by or adding of constants
Seven Growth Functions • Seven functions g(n) that occur frequently in the analysis of algorithms (in order of increasing rate of growth relative to n): • Constant 1 • Logarithmic log n • Linear n • Log Linear n log n • Quadratic n2 • Cubic n3 • Exponential 2n
Complexity Analysis • Asymptotic Complexity • Big-O (asymptotic) Notation • Big-O Computation Rules • Proving Big-O Complexity • How to determine complexity of code structures
Asymptotic Complexity • Finding the exact complexity, f(n) = number of basic operations, of an algorithm is difficult. • We approximate f(n) by a function g(n) in a way that does not substantially change the magnitude of f(n). --the function g(n) is sufficiently close to f(n) for large values of the input size n. • This "approximate" measure of efficiency is called asymptotic complexity. • Thus the asymptotic complexity measure does not give the exact number of operations of an algorithm, but it shows how that number grows with the size of the input. • This gives us a measure that will work for different operating systems, compilers and CPUs.
Big-O (asymptotic) Notation • The most commonly used notation for specifying asymptotic complexity is the big-O notation. • The Big-O notation, O(g(n)), is used to give an upper bound (worst-case) on a positive runtime function f(n) where n is the input size. Definition of Big-O: • Consider a function f(n) that is non-negative n 0. We say that “f(n) is Big-O of g(n)” i.e., f(n) = O(g(n)), if n0 0 and a constant c > 0 such that f(n) cg(n), n n0
Big-O (asymptotic) Notation Implication of the definition: • For all sufficiently large n, c *g(n) is an upper bound of f(n) Note: By the definition of Big-O: f(n) = 3n + 4 is O(n) it is also O(n2), it is also O(n3), . . . it is also O(nn) • However when Big-O notation is used, the function g in the relationship f(n) is O(g(n)) is CHOOSEN TO BE AS SMALL AS POSSIBLE. • We call such a function g a tight asymptotic bound of f(n)
Big-O (asymptotic) Notation Some Big-O complexity classes in order of magnitude from smallest to highest:
Warnings about O-Notation • Big-O notation cannot compare algorithms in the same complexity class. • Big-O notation only gives sensible comparisons of algorithms in different complexity classes when n is large . • Consider two algorithms for same task: Linear: f(n) = 1000 nQuadratic: f'(n) = n2/1000The quadratic one is faster for n < 1000000.
Rules for using big-O • For large values of input n , the constants and terms with lower degree of n are ignored. • Multiplicative Constants Rule: Ignoring constant factors. O(c f(n)) = O(f(n)), where c is a constant; Example: O(20 n3) = O(n3) 2. Addition Rule: Ignoring smaller terms. If O(f(n)) < O(h(n)) then O(f(n) + h(n)) = O(h(n)). Example: O(n2 log n + n3) = O(n3) O(2000 n3 + 2n ! + n800 + 10n + 27n log n + 5) = O(n !) 3. Multiplication Rule:O(f(n) * h(n)) = O(f(n)) * O(h(n)) Example: O((n3 + 2n 2 + 3n log n + 7)(8n 2 + 5n + 2)) = O(n 5)
Proving Big-O Complexity To prove that f(n) is O(g(n)) we find any pair of values n0 and c that satisfy: f(n) ≤ c * g(n) for n n0 Note: The pair (n0, c) is not unique. If such a pair exists then there is an infinite number of such pairs. Example: Prove that f(n) = 3n2 + 5 is O(n2) We try to find some values of n and c by solving the following inequality: 3n2 + 5 cn2 OR3 + 5/n2 c (By putting different values for n, we get corresponding values for c)
Proving Big-O Complexity Example: Prove that f(n) = 3n2 + 4n log n + 10 is O(n2) by finding appropriate values for c and n0 We try to find some values of n and c by solving the following inequality 3n2 + 4n log n + 10 cn2 OR 3 + 4 log n / n+ 10/n2 c ( We used Log of base 2, but another base can be used as well)
How to determine complexity of code structures Loops: for, while, and do-while: Complexity is determined by the number of iterations in the loop times the complexity of the body of the loop. Examples: for (int i = 0; i < n; i++) sum = sum - i; O(n) for (int i = 0; i < n * n; i++) sum = sum + i; O(n2) i=1; while (i < n) { sum = sum + i; i = i*2 } O(log n)
How to determine complexity of code structures Nested Loops: Complexity of inner loop * complexity of outer loop. Examples: sum = 0 for(int i = 0; i < n; i++) for(int j = 0; j < n; j++) sum += i * j ; O(n2) i = 1; while(i <= n) { j = 1; while(j <= n){ statements of constant complexity j = j*2; } i = i+1; } O(n log n)
How to determine complexity of code structures Sequence of statements: Use Addition rule O(s1; s2; s3; … sk) = O(s1) + O(s2) + O(s3) + … + O(sk) = O(max(s1, s2, s3, . . . , sk)) Example: Complexity is O(n2) + O(n) +O(1) = O(n2) for (int j = 0; j < n * n; j++) sum = sum + j; for (int k = 0; k < n; k++) sum = sum - l; System.out.print("sum is now ” + sum);
How to determine complexity of code structures char key; int[] X = new int[5]; int[][] Y = new int[10][10]; ........ switch(key) { case 'a': for(int i = 0; i < X.length; i++) sum += X[i]; break; case 'b': for(int i = 0; i < Y.length; j++) for(int j = 0; j < Y[0].length; j++) sum += Y[i][j]; break; } // End of switch block Switch: Take the complexity of the most expensive case o(n) o(n2) Overall Complexity: o(n2)
How to determine complexity of code structures • char key; • int[][] A = new int[5][5]; • int[][] B = new int[5][5]; • int[][] C = new int[5][5]; • ........ • if(key == '+') { • for(int i = 0; i < n; i++) • for(int j = 0; j < n; j++) • C[i][j] = A[i][j] + B[i][j]; • } // End of if block • else if(key == 'x') • C = matrixMult(A, B); • else • System.out.println("Error! Enter '+' or 'x'!"); If Statement: Take the complexity of the most expensive case : O(n2) Overall complexity O(n3) O(n3) O(1)
How to determine complexity of code structures • Sometimes if-else statements must carefully be checked: O(if-else) = O(Condition)+ Max[O(if), O(else)] int[] integers = new int[10]; ........ if(hasPrimes(integers) == true) integers[0] = 20; else integers[0] = -20; public boolean hasPrimes(int[] arr) { for(int i = 0; i < arr.length; i++) .......... .......... } // End of hasPrimes() O(1) O(1) O(n) O(if-else) = O(Condition) = O(n)
How to determine complexity of code structures while (n > 0) { if (n % 2 = = 0) { System.out.println(n); n = n / 2; } else{ System.out.println(n); System.out.println(n); n = n – 1; } } • Note: Sometimes a loop may cause the if-else rule not to be applicable. Consider the following loop: The else-branch has more basic operations; therefore one may conclude that the loop is O(n). However the if-branch dominates. For example if n is 60, then the sequence of n is: 60, 30, 15, 14, 7, 6, 3, 2, 1, and 0. Hence the loop is logarithmic and its complexity is O(log n)
Asymptotic Complexity • Running time of an algorithm as a function of input size n for large n. • Expressed using only the highest-order term in the expression for the exact running time. • Instead of exact running time, say Q(n2). • Describes behavior of function in the limit. • Written using Asymptotic Notation. Comp 122
Asymptotic Notation • Q, O, W • Defined for functions over the natural numbers. • Ex:f(n) = Q(n2). • Describes how f(n) grows in comparison to n2. • Define a set of functions; in practice used to compare two function sizes. • The notations describe different rate-of-growth relations between the defining function and the defined set of functions.
-notation For function g(n), we define (g(n)), big-Theta of n, as the set: (g(n)) ={f(n) : positive constants c1, c2, and n0,such that n n0, we have 0 c1g(n) f(n) c2g(n) } Intuitively: Set of all functions that have the same rate of growth as g(n). g(n) is an asymptotically tight bound for f(n).
O-notation For function g(n), we define O(g(n)), big-O of n, as the set: O(g(n)) ={f(n) : positive constants c and n0,such that n n0, we have 0 f(n) cg(n) } Intuitively: Set of all functions whose rate of growth is the same as or lower than that of g(n). g(n) is an asymptotic upper bound for f(n). f(n) = (g(n)) f(n) = O(g(n)). (g(n)) O(g(n)).
-notation For function g(n), we define (g(n)), big-Omega of n, as the set: (g(n)) ={f(n) : positive constants c and n0,such that n n0, we have 0 cg(n) f(n)} Intuitively: Set of all functions whose rate of growth is the same as or higher than that of g(n). g(n) is an asymptotic lower bound for f(n). f(n) = (g(n)) f(n) = (g(n)). (g(n)) (g(n)).
Relations Between Q, W, O Theorem : For any two functions g(n) and f(n), f(n) = (g(n))iff f(n) =O(g(n)) and f(n) = (g(n)). • I.e., (g(n)) = O(g(n)) ÇW(g(n)) • In practice, asymptotically tight bounds are obtained from asymptotic upper and lower bounds.
x = logba is the exponent for a = bx. Natural log: ln a = logea Binary log: lg a = log2a lg2a = (lg a)2 lglg a =lg(lg a) Logarithms
Review on Summations • Constant Series: For integers a and b, a b, • Linear Series (Arithmetic Series): For n 0, • Quadratic Series: For n 0,
Review on Summations • Cubic Series: For n 0, • Geometric Series: For real x 1, For |x| < 1,