60 likes | 240 Views
Day 4 - Notes. Unit: Thermochemistry. Limiting Reactants and Thermochemical Equations. After today you will be able to…. Use thermochemical equations to calculate limiting reactant. Recall, a limiting reactant is the reactant which yields the smaller amount of product.
E N D
Day 4 - Notes Unit: Thermochemistry Limiting Reactants and Thermochemical Equations
After today you will be able to… • Use thermochemical equations to calculate limiting reactant
Recall, a limiting reactant is the reactant which yields the smaller amount of product. • Energy in a chemical reaction can also help to determine which reactant limits the amount of product that can be made.
Example: How much energy is used when 14.3 moles of hydrosulfuric acid reacts with 17.1 moles of oxygen gas? 2H2S + 3O2 + 175 KJ 2SO2 + 2H2O 14.3 mol H2S x _________ = 17.1 mol O2 x ________ = K: 14.3 mol H2S U: ? kJ + 175 kJ +1250 kJ 2 mol H2S K: 17.1 mol O2 Used: U: ? kJ + 175 kJ +998 kJ 3 mol O2
3 2 1 Example: How much energy is produced when 13.11g of tin reacts with 2.715g of nitrogen? __ Sn + __ N2 __ Sn3N4 + 632 KJ 13.11 gSn x _________ x ________ = 2.715 gN2 x ________ x ________ = K: 13.11 gSn U: ? kJ Produced: 1 mol Sn -632 kJ -23.27 kJ 118.71 gSn 3 mol Sn K: 2.715 gN2 U: ? kJ 1 mol N2 -632 kJ -30.62 kJ 28.02 gN2 2 mol N2
Questions? Complete WS 4