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Chapter 4 Jeopardy!. Energy. Forces. Gravity. Mix. 500. 500. 500. 500. 400. 400. 400. 400. 300. 300. 300. 300. 200. 200. 200. 200. 100. 100. 100. 100. Final Jeopardy Question. Category 1 500 pts.
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Energy Forces Gravity Mix 500 500 500 500 400 400 400 400 300 300 300 300 200 200 200 200 100 100 100 100 Final Jeopardy Question
Category 1 500 pts A 10kg ball is dropped from a height of 5m. It lands on a spring (k=100N/m). 175 J are lost as friction in the fall. When the ball is moving 5m/s, how far is the spring compressed? GPE before hand = 10kg*10m/s/s*5m = 500J TE = 500J – 175J = 325J KE after = ½ 10kg (5m/s)2 = 125J SPE after = 325J – 125J = 200J 200J = ½ * 100N/m (x) 2 X2 = 200J / 50N/m = 4m2 X = 2m Back
Category 1 400 pts A 20kg ball is moving 20m/s when it rolls up a hill. How far up the hill does the ball make it? KE = ½ 20kg * (20m/s) 2 = 4000J GPE after = 4000J = 20kg * 10m/s/s * h h= 4000J/(20kg*10m/s/s) h = 4000J/200kgm/s/s h= 20m Back
Category 1 300 pts A 5kg ball is falling 10m/s at a height of 12 m and lands on a spring (k=150N/m). How far does the spring compress? KE = ½ * 5kg * (10m/s) 2 = 250J GPE = 5kg * 10m/s/s * 12m = 600J Total energy = 850J SPE = 850J = ½ 150N/m (x) 2 X2 = 850J / 75N/m = 11.33 m2 X= 3.36m Back
Category 1 200 pts A 15kg ball is compressed in a spring (k=100N/m) 3m. How high in the air will the ball make it? SPE = ½ 100N/m (3m) 2 = 450J GPE = 450J = 15kg * 10m/s/s * h h = 3m Back
Category 1 100 pts A 10kg ball is at a height of 50m and moving 10m/s. How much total energy does it have? TE = KE + GPE = ½ * 10kg * (10m/s) 2 + 10kg * 10m/s/s * 50m 500J + 5000J = 5500J Back
Category 2 500 pts A scale records 100kg person’s weight on an elevator as being 200N. Which direction and at what rate is the elevator accelerating? Fdown = 100kg* 10m/s/s = 1000N Fup = 200N Fnet = 800N down A = Fnet/m = 800N/100kg = 8m/s/s down Back
Category 2 400 pts A 75kg person is accelerating upwards on an elevator 4m/s/s. What weight would a scale say they weigh? Fnet = m*a = 75kg * 4m/s/s = 300N up Fdown = 75kg*10m/s/s = 750N Fup = 1050N Back
Category 2 300 pts A 20kg mass is hanging (not accelerating) from a spring (k=200N/m). How far does the spring stretch? Fdown = 20kg*10m/s/s = 200N Fup = 200N = 200N/m * x X = 1m Back
Category 2 200 pts A mass is stretching a spring (k=175N/m) 2m. What must be its mass? Fup = 175N/m * 2m = 350N Fdown = 350N = 10m/s/s * m m = 35kg Back
Category 2 100 pts Draw the FBD for a 10kg mass stretching a spring Back
Category 3 500 pts You have 4x as much mass as normal, but are 3x as far from the center of the Earth. What happens to the force of gravity 4x as much because of your mass, but 1/9th because of your distance So 4/9ths Back
Category 3 400 pts The acceleration of a 5kg person on Planet Physics is 100m/s/s. What is the weight of a 20kg dog on Physics Weight = Fg = m * g = 20kg * 100m/s/s = 2000N Back
Category 3 300 pts Planet Physics is 3x as big as Earth. Which accelerates at a greater rate, a 30kg mass on Earth, or a 10kg mass on Physics? Any object on Physics will accelerate at a greater rate Back
Category 3 200 pts An object has a weight of 30N. What is the mass? 30N/10m/s/s = 3kg Back
Category 3 100 pts A satellite is twice the distance from the center of the Earth. What is it’s acceleration? 10m/s/s /4 = 2.5m/s/s Back
Category 4 500 pts A 5kg mass is accelerating downwards 5m/s/s while attached to a spring (k=5N/m). How far is the spring stretched? Fnet = 5m/s/s * 5kg = 25N down Fg = 5kg *10m/s/s = 50N down Fs = 25N up 25N = 5N/m*x X = 5m Back
Category 4 400 pts An 5kg object stretches a spring (k=40N/m) 5m. Which way and at what rate does the object accelerate? Fup = 40N/m * 5m = 200N Fdown = 5kg * 10m/s/s = 50N Fnet = 150N up a = 150N/5kg = 30m/s/s Back
Category 4 300 pts A 5kg object stretches a spring 5m. What is the spring constant? How much SPE does the object have? K = F/x = 5kg*10m/s/s / 5m = 10N/m SPE = 1/2kx2 = ½ 10N/m * (5m) 2 SPE = 125J Back
Category 4 200 pts A 5kg object is on top of a 10m hill. At the bottom it is moving 10m/s/s. How much energy was lost as friction? GPE = 5kg * 10m/s/s * 10m = 500J KE at bottom = ½ 5kg * (10m/s) 2 = 250J Energy lost = 250J Back
Category 4 100 pts What does it mean to have a large spring constant? It takes a large force to stretch the spring Back
Final Jeopardy Name and define as many physics terms from this unit as you can Force, GPE, KE, SPE, Spring Force, Weight, Mass, Acceleration, Net Force, Velocity, Spring Constant, Gravity, Conservation, etc. You have 45 sec! Back