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Practical OP-AMP Circuits

Practical OP-AMP Circuits. Integrator. i. i. Differentiator. i. i. Voltage Subtractor or Difference Amplifier. Applying KCL at node ‘a’ , (V 1 – V 3 )/R 1 = (V 3 – V 0 )/R 2 (1) Applying KCL at node ‘b’,

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Practical OP-AMP Circuits

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  1. Practical OP-AMP Circuits

  2. Integrator i i

  3. Differentiator i i

  4. Voltage Subtractor or Difference Amplifier Applying KCL at node ‘a’, (V1 – V3)/R1 = (V3 – V0)/R2 (1) Applying KCL at node ‘b’, (V2 – V3)/R1 = V3/R2 (2) Rearranging (1), we get, (1/R1 + 1/R2)V3 – V1/R1 = V0/R2 (3) Rearranging (2), we get, (1/R1 + 1/R2)V3 – V2/R1 = 0 (4) (3) – (4), we get, (V2 – V1)/R1 = Vo/R2 or, Vo = R2(V2 – V1) /R1

  5. Ex.1) For the amplifier circuit find vo/v1

  6. Solution : io = i – i1 = vi/R1 – v/R= vi/R1 – (- iR)/R = vi/R1 + i = vi/R1 + vi/R1 = 2vi/R1 vo = v – ioR2 = - iR – 2viR2/R1 = - viR/R1 – 2viR2/R1 or, vo = - vi(R + 2R2)/R1 Hence, vo/vi = -(R + 2R2)/R1

  7. Ex.2) Find Vo in the following circuit.

  8. Solution V2 = V1 = 4/3 V Or, Vo – 4/3 = 2(4/3 +3) Or, Vo = 4/3 + 8/3 + 6 = 10 V

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