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Chapter 14. Fluids. Fluids at Rest. (Fluid = liquid or gas). Density ( r ). unit: kg/m 3 we will consider only r = m / V = constant (incompressible fluid) we will also assume g = constant. Pressure ( p ). A fluid exerts a force dF normal to any area dA you consider in it.
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Chapter 14 Fluids
Fluids at Rest (Fluid = liquid or gas)
Density (r) • unit: kg/m3 • we will consider only r = m/V = constant • (incompressible fluid) • we will also assume g = constant
Pressure (p) • A fluid exerts a force dF normal to any area dA you consider in it. • For a fluid at rest, the force is equal and opposite on each side.
Pressure (p) • Why is there a force? • Microscopically: the fluid particles are in motion and collide with dA • Macroscopically: the fluid is at rest
Pressure (p) • pressure p is a scalar (no intrinsic direction) • reason: it acts normal to any surface dA
Pressure (p) • units used:pascal, millibar, atm • 1 Pa = 1 N/m2 1 millibar = 100 Pa 1 atm = 1.013×105 Pa
Terminology • ‘gauge pressure’ = p – patm • (can be > 0 or < 0) • (e.g., read on a car tire pressure gauge) • p = absolute pressure (> 0) = atmospheric pressure + gauge pressure = patm + gauge pressure
Pressure and depth • pressure: pcoordinate: y • pressure decreases with ‘elevation’ y: Derive this result and integrate it
Pressure and depth • coordinate: ydistance: h > 0 • p increases with depthfor any shape of vessel Demonstration: depth and shape of container
Exercise 14-10 • The dangers of a long snorkel tube: • Find the gauge pressure at the depth shown. Will this cause the snorkeler’s lungs to collapse? Demonstration: atmospheric pressure
Pascal’s Law • If any change in pressure Dp is applied at one point, it is transmitted to all points in the fluid and to walls enclosing it.
Example: Hydraulic Lift At equilibrium, p = F1/A1 = F2/A2 Demonstration
Two Pressure Gauges Notes on (b) first Notes on (a) and Exercise 14-9
A (fully or partially) submerged object feels an upward force equal to the weight of fluid it displaces
(a) fluid element with weight wfluid(b) body of same shape feels buoyant force B = wfluid Demonstration
Surface Tension • Molecules of liquid attract each other (else no definite volume) • center: net force = 0 • surface: net force is directed inward
Surface Tension • So the surface acts like a membrane under tension (like a stretched drumhead) • The surface resists any change in surface area • Strength characterized by ‘surface tension’ Demonstration
Surface Tension g • g = F/d = cohesive force per unit length • surface tension forceF = g d • We can measure g by just balancing F Notes on measuring g Do Example 14-23
cohesion: attraction of like molecules example: liquid-liquid forces (surface tension)
adhesion: attraction between unlike moleculesexample: liquid-glass forces
(a) adhesion > cohesion: water wets glass(b) adhesion < cohesion: mercury beads up
Capillarity • For these two cases, the surface tension force F pushes the column of liquid either up or down: • (a) up for water • (b) down for mercury Notes on capillary tubes
Homework Announcements • Homework Set 5: Correction to hints for 14-55 (handout at front and on webpage) • Recent changes to classweb access (see HW 5 sheet at front and webpage) • Homework Sets 1, 2, 3: returned at front(scores to be entered on classweb soon)
Midterm Announcements • Friday: • review required topics • practice problems (from class, HW, new?) • Monday: (midterm) • you can bring a sheet of notes (both sides) • you will be given a list of equations
Fluid Flow (Fluid Dynamics)
Flow line =path of fluidelement Flow tube =bundle of flow lines passingthrough area A (just a useful construct) Flow Fluid
Steady flow: At any given point in the fluid, its properties (v, r, p) don’t change in time Simplifying Assumptions
Steady flow: different flow lines never cross each other fluid entering a flow tube never leaves it Simplifying Assumptions
Incompressible fluid: r = constant No friciton: no ‘viscosity’ Simplifying Assumptions
the same volume dV of fluid enters and exits tube: dV = volume passing through A in dt = Av dt Notes Continuity EquationA1v1 = A2v2
along the flow: A = area of flow tubev = speed of fluid if one increases, theother must decrease Continuity EquationA1v1 = A2v2 Notes and Demonstration: water flow
Where the flow lines are crowding together, the fluid speed is increasing Continuity EquationA1v1 = A2v2
only valid for:steady flow, incompressible fluid,no viscosity! Notes Bernoulli’s Equation
if v1= v2= 0: reduces to previous result for fluid at rest Bernoulli’s Equation
if y1= y2then for p and v: if one increases, theother must decrease Bernoulli’s Equation Demonstration
Notes Venturi Meter (Example 14-10) horizontal flow tube
Note: if viscosity is present, then v decreases with distance from tube center
Notes Venturi Meter:Homework Problem 14-90 (c) Demonstration
Can’t predict flow lines but they indicate low pressure above wing, so net force up Demonstration: propellor
First: you must fill the tube There is a limit:H + h < 10 m Siphon:flow tube points up, then down
Warm-up demonstrations Curve Ball:viscosity makes it possible
Viscosity drags air with spinning ball: low pressure=net force so the ball curves Demonstration
Homework Announcements • Homework Set 5: Correction to hints for 14-55 (handout at front and on webpage) • Recent changes to classweb access (see HW 5 sheet at front and webpage) • Homework Sets 1, 2, 3: returned at front(scores to be entered on classweb soon)