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Molar volume calculations. Molar volume calculations. a) Mass = g/cm x cm = 0.0143 g/cm x 3.00 cm = 0.042 9 g b) Moles = g x mol/g= 0.039 0 g x 1 mol/24.31 g = 0.0017 6 5 mol c) Moles H 2 = Moles Mg = 0.0017 6 5 mol ( should be higher # than g)
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Molar volume calculations a) Mass = g/cm x cm = 0.0143 g/cm x 3.00 cm = 0.0429 g b) Moles = g x mol/g= 0.0390 g x 1 mol/24.31 g = 0.001765 mol c) Moles H2 = Moles Mg = 0.001765 mol ( should be higher # than g) d) Class average = 44.1 mL e) 101.6 kPa, f) 22°C, 295 K g) 2.64 kPa (partial pressure of water) h) Pgas = Patm - Pvapour = (e – g) 101.6 kPa - 2.64 kPa = 98.96 kPa
P1V1 P2V2 = T1 T2 (98.96 kPa)(44.1 mL) (101.325 kPa)(V2) = (295 K) (273 K) (98.96 kPa)(44.1 mL)(273 K) = 39.86 mL (295 K)(101.325 kPa) V1 = 44.1 mL, P1 = 98.96 kPa, T1 = 295 K V2 = ?, P2 = 101.325 kPa, T2 = 273 K V2 = n) 0.001765 mol = 39.86 mL, 1 mol = 22587 mL (divide each side by 0.001765 or cross multiply) o) 22.59 – 22.4 (observed – expected / expected ) x 100 % % error = (22.59 - 22.4) / 22.4 x 100% = 0.19/22.4 x 100% = 0.85 % For more lessons, visit www.chalkbored.com