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Example . 2 2 2 The cross-sectional area A of a gutter with equal base and edge length of 2 is given by (trapezoidal area): Find the angle which maximizes the cross-sectional area of the gutter. Using an initial interval of find the solution after 2 iterations. Convergence achieved if “ interval length ” is within http://nm.mathforcollege.com
f1 f2 X2 X2=X1 X1 XL=X2 XL Xu Xu Solution The function to be maximized is Iteration 1: Given the values for the boundaries of we can calculate the initial intermediate points as follows: X1=? http://nm.mathforcollege.com
Solution Cont To check the stopping criteria the difference between and is calculated to be http://nm.mathforcollege.com
X2 XL Xu Solution Cont Iteration 2 X1 http://nm.mathforcollege.com
Theoretical Solution and Convergence The theoretically optimal solution to the problem happens at exactly 60 degrees which is 1.0472 radians and gives a maximum cross-sectional area of 5.1962. http://nm.mathforcollege.com
The End http://nm.mathforcollege.com
Acknowledgement This instructional power point brought to you by Numerical Methods for STEM undergraduate http://nm.mathforcollege.com Committed to bringing numerical methods to the undergraduate
For instructional videos on other topics, go to http://nm.mathforcollege.com This material is based upon work supported by the National Science Foundation under Grant # 0717624. Any opinions, findings, and conclusions or recommendations expressed in this material are those of the author(s) and do not necessarily reflect the views of the National Science Foundation.