150 likes | 271 Views
Miscellany. Xiaoyang Zhuang Economics 201FS Duke University March 16, 2010. Price Series. One-minute price data Alcoa. The world’s leading producer of aluminum. DuPont . A diversified scientific company. April 9, 1997 – December 30, 2010 3404 data points Aligned. Returns Series. *.
E N D
Miscellany XiaoyangZhuang Economics 201FS Duke University March 16, 2010
Price Series One-minute price data Alcoa. The world’s leading producer of aluminum. DuPont . A diversified scientific company. April 9, 1997 – December 30, 2010 3404 data points Aligned
Returns Series * ^ Five-minute returns data (overnight returns excluded) Alcoa. (*) October 10, 2008, 9:40 - 9:50: Standard & Poor’s revised the firm’s outlook from “stable” to “negative” after markets closed on October 9. [$11.76 11.82 12.43 12.54 13.09 $13.00 12.53 12.40 12.29 12.25 $12.04] DuPont. (^) May 6, 2010, 14:40 – 14:50: Flash crash. [$36.60 $34.10 $35.44]
Contents 1. Separating Market Microstructure Noise from the Price Process 2. Using Overnight Returns to Predict (Next-Day) Price Reversal
Contents 1. Separating Market Microstructure Noise from the Price Process 2. Using Overnight Returns to Predict (Next-Day) Price Reversal
Volatility Series Annualized, daily, one- and five-minute realized volatility data where t the day index, M is the number of intervals per day, and ∆ is the sampling interval size.
Market Microstructure Noise • Motivating Question • Given one-minute stock price data, is it possible to disentangle actual volatility from market microstructure noise? • The Idea • (*) The difference between realized volatilities calculated using x- and y-minute (x < y) returns data should be due to finite sample considerations and microstructure noise: • where RVolt,x-minute is the realized volatility on day t calculated using x-minute returns data; A is the difference due to finite sample considerations; and εmicrostructure is the difference due to microstructure noise. • The Percent of RVolt,xmin Not Accounted for by RVolt,(x+6)min seems to stabilize when x≥ ~6 (as we will see). • Could the stabilized value serve as an estimator of finite sample considerations as the sampling frequency changes?
(RVolt,1min - RVolt,6min)/ (RVolt,1min) Percent of RVolt,1min Not Accounted for by RVolt,6min Sample statistics: AA mean(Percent) =6.30 median(Percent) = 6.95 std(Percent) = 13.12 range(Percent) = [-57.40 50.55] Sample statistics: DD mean(Percent) = 8.00 median(Percent) = 8.24 std(Percent) = 13.73 range(Percent) = [-50.40 78.56]
(RVolt,6min - RVolt,11min)/ (RVolt,6min) Percent of RVolt,6min Not Accounted for by RVolt,11min Sample statistics: AA mean(Percent) =2.59 median(Percent) = 2.68 std(Percent) = 12.55 range(Percent) = [-62.97 52.65] Sample statistics: DD mean(Percent) = 3.62 median(Percent) = 3.55 std(Percent) = 12.56 range(Percent) = [-51.31 45.26]
(RVolt,11min - RVolt,16min)/ (RVolt,11min) Percent of RVolt,11min Not Accounted for by RVolt,16min Sample statistics: AA mean(Percent) =-0.79 median(Percent) = -0.45 std(Percent) = 14.76 range(Percent) = [-56.30 53.01] Sample statistics: DD mean(Percent) = -0.28 median(Percent) = 0.22 std(Percent) = 14.82 range(Percent) = [-85.91 59.17]
(RVolt,16min - RVolt,21min)/ (RVolt,16min) Percent of RVolt,16min Not Accounted for by RVolt,21min Sample statistics: AA mean(Percent) =0.82 median(Percent) = 1.16 std(Percent) = 16.03 range(Percent) = [-71.70 57.39] Sample statistics: DD mean(Percent) = 1.16 median(Percent) = 1.79 std(Percent) = 16.15 range(Percent) = [-78.41 49.66]
Can the mean of stable Percent values (i.e. x ≥ ~6) serve as an estimator of finite sample considerations?
Contents 1. Separating Market Microstructure Noise from the Price Process 2. Using Overnight Returns to Predict (Next-Day) Price Reversal
Overnight Returns and (Next-Day) Price Reversal Motivating Question Given that a stock loses value in afterhours trading, how will the stock perform in the first 15 minutes after the market opens the following morning? Procedure Define t as the day index. For each stock, consider every case in which the overnight return is negative: i.e. [pricet,15:59 pricet+1,9:35] = [x y], where x > y Compute a = max([pricet+1,9:36 pricet+1,9:37 . . . pricet+1,9:50]). Plot each (negative) overnight return against its corresponding Price Reversal, where Price Reversal = log(a) – log(pricet+1,9:35)
Overnight Returns and (Next-Day) Price Reversal Sample statistics: AA mean(Reversal) = 0.4281% median(Reversal) = 0.2552% % of Reversal data points exceeding 0: 74.8 Sample statistics: DD mean(Reversal) = 0.3441% median(Reversal) = 0.2309% % of Reversal data points exceeding 0: 77.0