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Positive Semidefinite matrix. A is a positive semidefinite matrix. (also called nonnegative definite matrix). Positive definite matrix. A is a positive definite matrix. Negative semidefinite matrix. A is a negative semidefinite matrix. Negative definite matrix.
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Positive Semidefinite matrix A is a positive semidefinite matrix (also called nonnegative definite matrix)
Positive definite matrix A is a positive definite matrix
Negative semidefinite matrix A is a negative semidefinite matrix
Negative definite matrix A is a negative definite matrix
Positive semidefinite matrix A is real symmetric matrix A is a positive semidefinite matrix
Positive definite matrix A is real symmetric matrix A is a positive definite matrix
Question Is It true that ? Yes
Fact 1.1.6 • The eigenvalues of a Hermitian (resp. positive semidefinite , positive definite) matrix are all real (resp. nonnegative, positive)
Exercise From this exercise we can redefinite: H is a positive semidefinite
注意 A is symmetric
注意 之反例 is not symmetric
Remark • Let A be an nxn real matrix. If λ is a real eigenvalue of A, then there must exist a corresponding real eigenvector. • However, if λ is a nonreal eigenvalue of A, then it cannot have a real eigenvector.
Explain of Remark p.1 • A, λ : real Az= λz, 0≠z (A- λI)z=0 By Gauss method, we obtain that z is a real vector.
Explain of Remark p.2 • A: real, λ is non-real Az= λz, 0≠z z is real, which is impossible
Elementary symmetric function kth elementary symmetric function
KxK Principal Minor kxk principal minor of A
Rank P.1 rankA:=the maximun number of linear independent column vectors =the dimension of the column space = the maximun number of linear independent row vectors =the dimension of the row space result result
Rank P.2 rankA:=the number of nonzero rows in a row-echelon (or the reduced row echlon form of A)
Rank P.3 rankA:=the size of its largest nonvanishing minor (not necessary a principal minor) =the order of its largest nonsigular submatrix. See next page
Rank P.4 1x1 minor Not principal minor rankA=1
Theorem Let A be an nxn sigular matrix. Let s be the algebraic multiple of eigenvalue 0 of A. Then A has at least one nonsingular (nonzero)principal submatrix(minor) of order n-s.
Geometric multiple Let A be a square matrix and λ be an eigenvalue of A, then the geometric multiple of λ=dimN(λI-A) the eigenspace of A corresponding to λ
Exercise A and have the same characteristic polynomial and moreover the geometric multiple and algebraic multiple are similarily invariants.
Proof of Exercise p.2 (2)Since A and have the same characteristic polynomial, they have the same eigenvalues and the algebraic multiple of each eigenvalue is the same.
Fact For a diagonalizable(square) matrix, the algebraic multiple and the geometric multiple of each of its eigenvalues are equal.
Corollary Let A be a diagonalizable(square) matrix and if r is the rank of A, then A has at least one nonsingular principal Submatrix of order r.