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Tarea #10

Tarea #10. Oswaldo Acu ña V elandia G1N01Oswaldo. Tarea No 10. Para el color verde en el espectro electromagnético su longitud de onda es 5000 Amstrongs . Calcule: su frecuencia su energía en Julios y en electrones-Voltios.

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Tarea #10

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  1. Tarea#10 OswaldoAcuñaVelandia G1N01Oswaldo

  2. Tarea No 10 • Para el color verde en el espectro electromagnético su longitud de onda es 5000 Amstrongs.Calcule: • su frecuencia • su energía en Julios y en electrones-Voltios. • Haga lo mismo para otras regiones del espectro electromagnético

  3. Color Verde 5000 Amstrongs * 1E-10 m = 5 E -7 metros = λ 1armstrong C= λ*f C/ λ =f C= 3E 8 m/s f = 3 E8 m/s / 5E-7 m= 6 E14 Hz = 6 E8 MHz E= h*f h= 6,6E-34 J/s E= 6,6E-34 J/s* 6 E14 Hz = 3,96 E-19 J 3,96 E-19 J* 1 eV/ 1,6 E-19 J = 2,475 eV

  4. Rayos x 10 nm>λ> 0,01 nm 10 nm*1E -9 m/ 1 nm = 1 E-8 m C= λ*f C/ λ =f C= 3E 8 m/s f = 3 E8 m/s / 1 E-8 m = 3 E16 Hz E= h*f h= 6,6E-34 J/s E= 6,6E-34 J/s* 3 E16 Hz = 1,98 E-17 J 3,96 E-19 J* 1 eV/ 1,6 E-19 J = 123,75 eV

  5. Rayos X 0,01nm *1E -9 m/ 1 nm = 1 E-11 m C= λ*f C/ λ =f C= 3E 8 m/s f = 3 E8 m/s / 1 E-11 m = 3 E19 Hz E= h*f h= 6,6E-34 J/s E= 6,6E-34 J/s* 3 E19 Hz = 1,98 E-14 J 3,96 E-19 J* 1 eV/ 1,6 E-19 J = 123750 eV

  6. RangoRayos x

  7. Microondas (1 m>λ> 1 nm) λ=1 nm 1 nm*1E -9 m/ 1 nm = 1 E-9 m C= λ*f C/ λ =f C= 3E 8 m/s f = 3 E8 m/s / 1 E-9 m = 3 E17 Hz E= h*f h= 6,6E-34 J/s E= 6,6E-34 J/s* 3 E17 Hz = 1,98 E-16 J 3,96 E-19 J* 1 eV/ 1,6 E-19 J = 1237,5 eV

  8. 1 m=λ C= λ*f C/ λ =f C= 3E 8 m/s f = 3 E8 m/s / 1 m = 3 E 8 Hz E= h*f h= 6,6E-34 J/s E= 6,6E-34 J/s* 3 E8 Hz = 1,98 E-25 J 3,96 E-19 J* 1 eV/ 1,6 E-19 J = 1,2375 E-6 eV

  9. RangoMicroondas

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