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GUPPESS. Problem solving approach G iven U nknowns P icture P rinciple E quation(s) (Governing) S olve (Algebra first!) S ubstitute (given values). Example.
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GUPPESS • Problem solving approach • Given • Unknowns • Picture • Principle • Equation(s) (Governing) • Solve (Algebra first!) • Substitute (given values)
Example • A sample of an ideal gas is held at 110 kPa within 15 liters volume. Its temperature is 300o Kelvin. How many moles of the gas are in the sample?
Given • What quantities are provided in the problem statement with a value? • Pressure = 110 kPa • Volume = 15 Liters • Temperature = 300 Kelvin
Unknowns • Quantity of gas, number of moles.
Principle • What is the principle you can use to describe the situation portrayed? • Ideal Gas Behavior
Equation • What equation do you know, or you can find, that quantifies a relationship between the givens and unknowns? • Ideal gas law • PV=nRT • P=Pressure, V=volume, n=number of moles, R=ideal gas constant, T= temperature in degrees Kelvin
Solve • Algebra first • you’ll make less math/calculator mistakes • you can retrace your work after to double check it. • PV=nRT; n=PV/RT
Substitute • Givens explicitly provided in the problem statement, and some values, such as constants that you may need to look up.
May need to convert! • R=0.08206 (Latm/mol K)(101.3 kPa/atm) =8.31 kPaL/mol K
Kinematics Equations • v = vo + at • x=x0+vot+½ at2 • v2 = vo2 + 2aDx • Dx = ½ (vo+ v)t v=velocity a=acceleration(constant) x=position t=time subscript 0 means initital
Now you try • A block slides down a ramp. At the 10 cm mark its velocity is 5 cm/s, after 30 more cm, its velocity has increased to 15 cm/sec. Assuming uniform acceleration, what is the value of the acceleration?
Given • What quantities are provided in the problem statement with a value? • x0 = 0.10 m • Dx= 0.30 m • vo= 0.05 m/sec • vf = 0.15 m/sec
Unknowns • Acceleration down ramp
Principle • What is the principle you can use to describe the situation as portrayed? • Kinematics, motion in one dimension
Equation • Pick one that has your knowns and the quantity you need to find v2 = vo2 + 2aDx
Solve • Algebra first • you’ll make less math/calculator mistakes • you can retrace your work after to double check it. v2 = vo2 + 2aDx; a=(v2-v02)/2Dx
Substitute • Givens explicitly provided in the problem statement, and some values, such as constants that you may need to look up.