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Vocabulary. The Angle Addition Postulate. What You'll Learn. You will learn to find the measure of an angle and the bisector of an angle. NOTHING NEW!. R. S. T. The Angle Addition Postulate. 1) Draw an acute, an obtuse, or a right angle. Label the angle RST. R.
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Vocabulary The Angle Addition Postulate What You'll Learn You will learn to find the measure of an angle and the bisectorof an angle. NOTHING NEW!
R S T The Angle Addition Postulate 1) Draw an acute, an obtuse, or a right angle. Label the angle RST.
R X 2) Draw and label a point X in the interior of the angle. Then draw SX. S T The Angle Addition Postulate 1) Draw an acute, an obtuse, or a right angle. Label the angle RST.
R X 2) Draw and label a point X in the interior of the angle. Then draw SX. S T The Angle Addition Postulate 1) Draw an acute, an obtuse, or a right angle. Label the angle RST. 3) For each angle, find mRSX, mXST, and RST.
R X 2) Draw and label a point X in the interior of the angle. Then draw SX. S T The Angle Addition Postulate 1) Draw an acute, an obtuse, or a right angle. Label the angle RST. 45° 30° 3) For each angle, find mRSX, mXST, and RST.
R X 2) Draw and label a point X in the interior of the angle. Then draw SX. S T The Angle Addition Postulate 1) Draw an acute, an obtuse, or a right angle. Label the angle RST. 45° 75° 30° 3) For each angle, find mRSX, mXST, and RST.
R X S T The Angle Addition Postulate 1) How does the sum of mRSX and mXST compare to mRST ? 45° 75° 30°
R X S T The Angle Addition Postulate 1) How does the sum of mRSX and mXST compare to mRST ? Their sum is equal to the measure of RST . mXST = 30 + mRSX = 45 = mRST = 75 45° 75° 30°
R X S T The Angle Addition Postulate 1) How does the sum of mRSX and mXST compare to mRST ? Their sum is equal to the measure of RST . mXST = 30 + mRSX = 45 = mRST = 75 2) Make a conjecture about the relationship between the two smaller angles and the larger angle. 45° 75° 30°
R X S T The Angle Addition Postulate 1) How does the sum of mRSX and mXST compare to mRST ? Their sum is equal to the measure of RST . mXST = 30 + mRSX = 45 = mRST = 75 2) Make a conjecture about the relationship between the two smaller angles and the larger angle. 45° The sum of the measures of the twosmaller angles is equal to the measureof the larger angle. 75° 30°
P 1 Q A 2 R The Angle Addition Postulate
P 1 Q A 2 R The Angle Addition Postulate m1 + m2 = mPQR.
P 1 Q A 2 R The Angle Addition Postulate m1 + m2 = mPQR. There are two equations that can be derived using Postulate 3 – 3.
P 1 Q A 2 R The Angle Addition Postulate m1 + m2 = mPQR. There are two equations that can be derived using Postulate 3 – 3. m1 = mPQR –m2 m2 = mPQR –m1
P 1 Q A 2 R The Angle Addition Postulate m1 + m2 = mPQR. There are two equations that can be derived using Postulate 3 – 3. m1 = mPQR –m2 These equations are true no matter where A is locatedin the interior of PQR. m2 = mPQR –m1
X 1 Y W 2 Z The Angle Addition Postulate Find m2 if mXYZ = 86 and m1 = 22.
X 1 Y W 2 Z The Angle Addition Postulate Find m2 if mXYZ = 86 and m1 = 22. Postulate 3 – 3. m2 + m1 = mXYZ
X 1 Y W 2 Z The Angle Addition Postulate Find m2 if mXYZ = 86 and m1 = 22. Postulate 3 – 3. m2 + m1 = mXYZ m2 = mXYZ –m1
X 1 Y W 2 Z The Angle Addition Postulate Find m2 if mXYZ = 86 and m1 = 22. Postulate 3 – 3. m2 + m1 = mXYZ m2 = mXYZ –m1 m2 = 86 – 22
X 1 Y W 2 Z The Angle Addition Postulate Find m2 if mXYZ = 86 and m1 = 22. Postulate 3 – 3. m2 + m1 = mXYZ m2 = mXYZ –m1 m2 = 86 – 22 m2 = 64
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120.
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3.
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3. Substitution 2x + (5x – 6) = 120
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3. Substitution 2x + (5x – 6) = 120 7x – 6 = 120 Combine like terms
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3. Substitution 2x + (5x – 6) = 120 7x – 6 = 120 Combine like terms 7x = 126 Add 6 to both sides
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3. Substitution 2x + (5x – 6) = 120 7x – 6 = 120 Combine like terms 7x = 126 Add 6 to both sides x = 18 Divide each side by 7
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3. Substitution 2x + (5x – 6) = 120 7x – 6 = 120 Combine like terms 7x = 126 Add 6 to both sides x = 18 Divide each side by 7 mABC = 2x mABC = 2(18) mABC = 36
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3. Substitution 2x + (5x – 6) = 120 7x – 6 = 120 Combine like terms 7x = 126 Add 6 to both sides x = 18 Divide each side by 7 mCBD = 5x – 6 mABC = 2x mCBD = 5(18) – 6 mABC = 2(18) mCBD = 90 – 6 mABC = 36 mCBD = 84
C D (5x – 6)° 2x° B A The Angle Addition Postulate Find mABC and mCBD if mABD = 120. mABC + mCBD = mABD Postulate 3 – 3. Substitution 2x + (5x – 6) = 120 7x – 6 = 120 Combine like terms 7x = 126 Add 6 to both sides x = 18 Divide each side by 7 36 + 84 = 120 mCBD = 5x – 6 mABC = 2x mCBD = 5(18) – 6 mABC = 2(18) mCBD = 90 – 6 mABC = 36 mCBD = 84
The Angle Addition Postulate Just as every segment has a midpoint that bisects the segment, every angle has a ___ that bisects the angle.
The Angle Addition Postulate Just as every segment has a midpoint that bisects the segment, every angle has a ___ that bisects the angle. ray
The Angle Addition Postulate Just as every segment has a midpoint that bisects the segment, every angle has a ___ that bisects the angle. ray This ray is called an ____________ .
The Angle Addition Postulate Just as every segment has a midpoint that bisects the segment, every angle has a ___ that bisects the angle. ray angle bisector This ray is called an ____________ .
The Angle Addition Postulate Just as every segment has a midpoint that bisects the segment, every angle has a ___ that bisects the angle. ray angle bisector This ray is called an ____________ .
P 1 Q A 2 R The Angle Addition Postulate
is the bisector of PQR. P 1 Q A 2 R The Angle Addition Postulate
is the bisector of PQR. P 1 Q A 2 R The Angle Addition Postulate m1 = m2
N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2.
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2.
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2. 1 + 2 = CAN Postulate 3 - 3
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2. 1 + 2 = CAN Postulate 3 - 3 Replace CAN with 130 1 + 2 = 130
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2. 1 + 2 = CAN Postulate 3 - 3 Replace CAN with 130 1 + 2 = 130 1 + 1 = 130 Replace 2 with 1
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2. 1 + 2 = CAN Postulate 3 - 3 Replace CAN with 130 1 + 2 = 130 1 + 1 = 130 Replace 2 with 1 2(1) = 130 Combine like terms
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2. 1 + 2 = CAN Postulate 3 - 3 Replace CAN with 130 1 + 2 = 130 1 + 1 = 130 Replace 2 with 1 2(1) = 130 Combine like terms (1) = 65 Divide each side by 2
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2. 1 + 2 = CAN Postulate 3 - 3 Replace CAN with 130 1 + 2 = 130 1 + 1 = 130 Replace 2 with 1 2(1) = 130 Combine like terms (1) = 65 Divide each side by 2 Since 1 = 2
Since bisects CAN, 1 = 2. N T 2 1 A C The Angle Addition Postulate If bisects CAN and mCAN = 130, find 1 and 2. 1 + 2 = CAN Postulate 3 - 3 Replace CAN with 130 1 + 2 = 130 1 + 1 = 130 Replace 2 with 1 2(1) = 130 Combine like terms (1) = 65 Divide each side by 2 Since 1 = 2, 2 = 65
The Angle Addition Postulate End of Lesson