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JEOPARDY! Geometry Bench Mark 1 Review

JEOPARDY! Geometry Bench Mark 1 Review. All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER! All students will play EVERY ROUND and show work on a separate sheet of paper (to be turned in).

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JEOPARDY! Geometry Bench Mark 1 Review

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  1. JEOPARDY! Geometry Bench Mark 1 Review • All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER! • All students will play EVERY ROUND and show work on a separate sheet of paper (to be turned in). • Students will keep score together – winner gets bonus credit.

  2. Building Blocks Be Reasonable It’s Moving Time Angle Madhouse Straight As An Arrow 100 100 100 100 100 200 200 200 200 200 300 300 300 300 300 400 400 400 400 400 500 500 500 500 500 Go To Final Jeopardy!

  3. 100 Solve for x: M is the midpoint of AB. AM = 4x + 19 BM = 2x + 13

  4. 100 What is ? Question: M is the midpoint of AB. AM = 4x + 19 BM = 2x + 13

  5. 200 A, B and C are collinear and B lies between A and C. If AB = 2x + 4, BC = 12, AC = 4x – 6, then find AC.

  6. A, B and C are collinear and B lies between A and C. If AB = 2x + 4, BC = 12, AC = 4x – 6, then find AC. 200 First, 2x + 4 + 12 = 4x – 6 x = 11 Therefore, AC = 38

  7. 300 O is the midpoint of FX. If FO = 3x + 6 and FX = 66, then solve for x.

  8. 300 3x + 6 = ½  66 x = 9

  9. 400 C is the midpoint of AE. If A is located at (7, 1) and C is located at (2, –3), then find the coordinates of E.

  10. C is the midpoint of AE. If A is located at (7, 1) and C is located at (2, –3), then find the coordinates of E. C is in the middle!!! From A to C, we go left 5 and down 4, so if we do it again, we end up at E = (–3, –7) 400

  11. 500 Find the midpoint of AB if A is located at (a + c, d – e) and B is located at (g – h, s + t).

  12. Find the midpoint of AB if A is located at (a + c, d – e) and B is located at (g – h, s + t). 500

  13. 100 Ray OX lies in the interior of BOD. If mBOX = 2x + 9, mDOX = 3x – 2, and mBOD = 72, find mBOX.

  14. Ray OX lies in the interior of BOD. If mBOX = 2x + 9, mDOX = 3x – 2, and mBOD = 72, find mBOX. 100 2x + 9 + 3x – 2 = 72 x = 13 mBOX = 35

  15. 200 A and B are complementary. If mA = 2x + 4 and mB = 7x - 22, find mB.

  16. A and B are complementary. If mA = 2x + 4 and mB = 7x - 22, find mB. 200 2x + 4 + 7x – 22 = 90 x = 12 mB = 62

  17. 300 A and B are a linear pair. If mA = 70 – 2x and mB = 8x – 10, find mB.

  18. A and B are a linear pair. If mA = 70 – 2x and mB = 8x – 10, find mB. 300 70 – 2x + 8x – 10 = 180 6x + 60 = 180 x = 20 mB = 150

  19. 400 Ray UP bisects TUX. If mTUP = 3x + 4 and mTUX = 104, solve for x.

  20. Ray UP bisects TUX. If mTUP = 3x + 4 and mTUX = 104, solve for x. 400 3x + 4 = ½  104 3x = 48 x = 16

  21. 500 Based on the following, find mDXC. B (5x – 40)° A C X (2x + 2)° D

  22. 500 5x – 40 = 2x + 2 (vertical angles) x = 14 Plugging in… mAXD = 30 THEREFORE, mDXC = 180 – 30 = 150 B (5x – 40)° A C X (2x + 2)° D

  23. B B' A A' C C' 100 Identify the following construction and the first step used to construct it.

  24. 100 Copy a (congruent) angle. Step 1: Draw a new ray and label the vertex A’.

  25. C' C A A' 200 Identify the following construction and the first step used to construct it.

  26. 200 Copy a (congruent) segment. Step 1: Draw a new ray and label the vertex A’.

  27. 300 Identify the following construction and the first step used to construct it. A B

  28. 300 Bisect a segment. Step 1: From both A and B, draw large arcs that intersect each other and AB.

  29. 400 Identify the following construction and the first step used to construct it. C D A B

  30. 400 Bisect an angle Step 1: From A, draw an arcs that intersects the angle and label points B and C.

  31. 500 List all the steps needed to copy a congruent angle.

  32. B B' A A' C C' 500 Step 1. Draw a new ray and label the endpoint A’. Step 2. From A, draw an arc through the angle and label the intersections B and C. From A’, draw the same arc and label C’. Step 3. Measure from C to B. Draw a small arc and use the same arc when measuring from C’. Label B’. Step 4. Draw a ray from A’ to B’ – we’re done.

  33. 100 Point A is at (2, 5) and Point B is at (–3, 7). Find the new location of each point when they are translated according to the motion rule: (x, y)  (x – 6, y + 1)

  34. Point A is at (2, 5) and Point B is at (–3, 7). Find the new location of each point when they are translated according to the motion rule: (x, y)  (x – 6, y + 1) 100 A’ is at (–4, 6) B’ is at (–9, 8)

  35. 200 Point A is at (3, 4) and Point B is at (–1, –5). Find the new location of each point when they are translated 2 units up and 4 units left.

  36. Point A is at (3, 4) and Point B is at (–1, –5). Find the new location of each point when they are translated 2 units up and 4 units left. 200 Be careful…read the question… (up 2 = y + 2, left 4 = x – 4) A’ is at (–1, 6) B’ is at (–5, –3)

  37. 300 When A (–5, 2) and B (–3, 6) are reflected about the y-axis, the new coordinates of B’ are:

  38. When A (–5, 2) and B (–3, 6) are reflected about the y-axis, the new coordinates of B’ are: 300 (3, 6)

  39. 400 Point A (6, –4) is first reflected about the origin, then reflected about the x-axis. The new coordinates of A’ are:

  40. Point A (6, –4) is first reflected about the origin, then reflected about the x-axis. The new coordinates of A’ are: It first moves to (–6, 4), then it moves to (–6, –4). 400

  41. 500 Daily Double

  42. 500 A (–7, 2) is rotated 90 counterclockwise. Find the location of A’.

  43. 500 The x-dimension and y-dimension switch every 90 and one sign changes. Since we rotated “left”, both the x and y became negative. (–2, –7)

  44. 100 Define inductive and deductive reasoning. Identify key phrases to help identify each type.

  45. 100 Inductive = INFERRING GENERAL TRUTHS based upon SPECIFIC EXAMPLES or a PATTERN Deductive = USING LOGIC to DRAW CONCLUSIONS based upon ACCEPTED STATEMENTS.

  46. 200 “If Noah studies well, then Noah earns 100% on the test.” Write the converse and the contrapositive statements.

  47. “If Noah studies well, then Noah earns 100% on the test.” 200 Converse: (Switch the If and then parts) “If Noah earns 100% on the test, then Noah studied well.” Contrapositive (switch AND negate it) “If Noah does NOT earn 100% on the test, then Noah did NOT study well.”

  48. 300 “Two lines in a plane always intersect to form right angles.” Find one or more counterexamples.

  49. “Two lines in a plane always intersect to form right angles.” Find one or more counterexamples. 300 • Non-perpendicular, intersecting lines in the same plane • Parallel lines in the same plane. • They have to be lines that LIE IN THE SAME PLANE.

  50. 400 • Complete the proof reasons: • Statements Reasons • 3x + 6 = 39 1. Given • 3x = 33 2. ___________ • x = 11 3. ___________

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