1 / 25

Application A Simple Model of Paramagnetism Section 6.3 ( Spin = ½ ) Section 7.8 ( Spin = S )

Application A Simple Model of Paramagnetism Section 6.3 ( Spin = ½ ) Section 7.8 ( Spin = S ). Paramagnetic Materials: Spin J. Consider a solid in which all of the magnetic ions are identical, having the same value of J (appropriate for the ground state).

prenee
Download Presentation

Application A Simple Model of Paramagnetism Section 6.3 ( Spin = ½ ) Section 7.8 ( Spin = S )

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Application A Simple Model of Paramagnetism Section 6.3 (Spin = ½) Section 7.8 (Spin = S)

  2. Paramagnetic Materials: Spin J • Consider a solid in which all of the magnetic ions • are identical, having the same value of J • (appropriate for the ground state). • Every value of Jz is equally likely, so the average value of the ionic dipole moment is zero. • When a field is applied in the positive z direction, states of differing values of Jz will have differing energies and differing probabilities of occupation. • The zcomponent of the moment is: • and its energy is

  3. Recall the equation for the magnetic moment of an atom, i. e. Where g is the Lande’ splitting factor given as, Consider only spin,

  4. Consider only orbital motion, Let N be the number of atoms or ions/ m3 of a paramagnetic material. The magnetic moment of each atom is, In presence of magnetic field, according to space quantization. Where MJ = –J, -(J-1),…,0,…(J-1), J i.e. MJ will have (2J+1) values.

  5. The magnetic moment of an atom along the magnetic field corresponding to a given value of MJ is thus, If dipole is kept in a magnetic field B then potential energy of the dipole would be Therefore, Boltzmann factor would be, Represents fraction of dipoles with energy MjgBB. The magnetic moment of such atoms would be Thus, average magnetic moment of atoms of the paramagnetic material would be

  6. Average magnetic moment Therefore, magnetization would be Case 1: Let,

  7. Since Mj = -J, -(J-1),….,0,….,(J-1), J, therefore, Simplifying this equation, we get

  8. Let a = xJ, above equation may be written as, Here, BJ(a) = Brillouin function.

  9. The maximum value of magnetization would be Thus, For J = 1/2 For J = 

  10. Case 2: But Thus above equation becomes,

  11. Thus where, where, This is curie law. Further, Thus Peff is effective number of Bohr Magnetons. C is Curie Constant. Obtained equation is similar to the relation obtained by classical treatment.

  12. High T ( x << 1 ): Curie-Brillouin law: Brillouin function:

  13. High T ( x << 1 ): Curie law = effective number of Bohr magnetons Gd (C2H3SO4)  9H2O

  14. Brillouin Function Brillouin Function As a result of these probabilities, the average dipole moment is given by

  15. Brillouin Function

  16. Curie Law The Curie constant can be rewritten as where p is the effective number of Bohr magnetons per ion.

  17. The J=1/2 case Two spins, J=1/2, just two states (parallel or AP), to average statistically Several similarities Estimate the paramagnetic susceptibility

  18. Generic J and the Brillouin function

  19. Lande’ g-value and effective moment J=1/2 J=3/2 J=5 Curie law: c=CC/T

  20. (2.828)2χT=g2S(S+1)

More Related