ACC. AAF Quiz #3 - Key

1. ACCUPLACER Module #3 - AAF Quiz #3 - Key 1

2. Module #3 Quiz #3 1. D: The correct solution is 4 because The diameter is twice the radius, or about 4.0 feet. 2. A: The correct solution is 669.3. centimeters. 3. D: The correct solution is 69.08 because centimeters. 4. B: The correct solution is points x and u are vertices of angles because points are the intersection of two rays. 5. D: The correct solution is a translation left 3 units and down 4 units because the points (x, y) become (x-3, y-4). 6. B: The answers A, C, and D all contain composite numbers (6, 10, and 15). Therefore answer B is correct. 7. D: Each statement about x and y is true. 8. D: The leaves of a factor tree in a prime factorization are prime factors. But the branches, because they are not leaves, are composite -yet they are still factors of the number undergoing prime factorization. Branches may be odd or even because some composite numbers are odd and some are even. 9. B: The correct solution is 523.33 cubic inches. The radius is 5 inches. Substitute the values into the formula and simplify using the order of operations. 4 4 4 (3.14)5 (3.14)(125) 523.33 3 3 3 10. D: The correct solution is 4 feet. Substitute the values into the formula 16 2 3 3 feet, and double the radius to find the diameter of 4 feet. NAME: _____KEY_________________         . 2 2 2 12 3.14 3.82 2.0 A r r r r         2 92 (3.14) 92 6.28 14.6 C r r r r     2 (2)(3.14)(11) 69.08 C r      3 3 cubic inches. V r     3 3 , multiply both sides by the reciprocal, . Apply the cube root, r = 2 8 r r 2

3. 11. C: The correct solution is 6 inches. Substitute the values into the formula, 1 2 (1) 3 1 2 (1) 3 divide by ? to get a solution of 6 inches. 12. B: The correct solution is (-10, 10) because 30 can be added to the y-coordinate, -20 + 30 = 10. 13. C: The correct solution is 12 units. The difference between the x-coordinates is 6 - (-6) = 12 units. 14. A: The correct solutions are -15.73 and -1.27. The equation can be solved by the quadratic formula. 17 17 4(1)(20) 2(1) 17 289 80 2 17 209 2 17 14.46 2 17 14.46 17 14.46 , 2 2 2.54 1.27 2 31.46 15.73 2    2 and simplify using the right side of the equation by applying the h 1 3        exponent and multiplying, Multiply both sides by 3 and 2 . h h    2  Substitute 1 for a, 17 for b, and 20 for c. x     Apply the exponent and the multiplication. x    Perform the subtraction. x    Apply the square root. x       Separate the problem into two expressions. x x     Simplify the numerator and divide. x     x 3