ACC AAF W/S #3 Key

1. ACCUPLACER® Module #3 - AAF Worksheet #3 - Key 1

2. Module #3 Worksheet #3 1. D: Using SOH-CAH-TOA, tangent is y NAME: _____KEY_________________ for the special triangles. Since the value x . needs to be a negative one, the angle must be some form of 45 degrees or 4 The value is negative in the second and fourth quadrant, so the answer is 3 and 4  7 . 4 2. D: The inverse of a function is found by following these steps: 1. Change f(x) to y. 2. Switch the x and y. 3. Solve for y. In the given equation, solving for y is done by adding 5 to both sides, then dividing both sides by 3. This answer can be checked on the graph by verifying the lines are reflected over y = x. 3. B: The zeros of this function can be found by using the quadratic formula: 4 2 a because it is in standard form. The formula becomes: 0 0 4(1)(4) 16 2 2(1) 2 the answer is a complex number.    2 b b ac  . Identifying a, b, and c can be done from the equation as well x   2      . Since there is a negative underneath the radical, x i 2

3. 4. B: The y-intercept of an equation is found where the x-value is zero. Plugging zero into the equation for x, the first two terms cancel out, leaving -4. 5. A: The equation is even because f(-x) = f(x). Plugging in a negative value will result in the same answer as when plugging in the positive of that same value. 1 ( 2) ( 2) 2( 2) 6 8 8 6 10 2 1 (2) (2) 2(2) 6 8 8 6 10 2 f           4 2 The function: yields the same value as:        4 2 . f 3