1 / 7

Structural Mechanics 4 Shear Force, Bending Moment and Deflection of Beams

Structural Mechanics 4 Shear Force, Bending Moment and Deflection of Beams. 20 kN. R A. R B. 3.00m. 2.00m. Sum of moments about R A = 0. 20 x (2.00) - R B x (2.00 +3.00) = 0 R B x (5.00) = 20 x (2.00) R B = 20 x (2.00) / (5.00)

quasim
Download Presentation

Structural Mechanics 4 Shear Force, Bending Moment and Deflection of Beams

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Structural Mechanics 4Shear Force, Bending Moment and Deflection of Beams 20 kN RA RB 3.00m 2.00m

  2. Sum of moments about RA = 0 • 20 x (2.00) - RB x (2.00 +3.00) = 0 • RB x (5.00) = 20 x (2.00) • RB = 20 x (2.00) / (5.00) • RB = 8.00 kN

  3. Sum of moments about RB = 0 • RA x (2.00 +3.00) - 20 x (3.00) = 0 • RA x (5.00) = 20 x (3.00) • RA = 20 x (3.00) / (5.00) • RA = 12.00 kN

  4. CHECK VERTICAL FORCES • UPWARD REACTION = RB + RA = 8 + 12 = 20 kN • DOWNWARD FORCE = 20 kN • So likely that calculations are correct!

  5. SHEAR FORCE DIAGRAM Space diagram SHEAR FORCE DIAGRAM 20 kN 8kN 12kN 12kN 0 -8kN

  6. BENDING MOMENT DIAGRAM • Space diagram 20 kN 12kN 8kN 24kNm 0kNm 12kN X 2m = 24 kNm 8kN X 3m = 24 kNm

  7. Deflection 20 kN Max deflection at Max BM 12kN 8kN 24kNm SFD + 12kN 0 0kNm BMD

More Related