1 / 20

ECE 3710 E: Circuits and Electronics

ECE 3710 E: Circuits and Electronics. Jeff Dugger. Lecture 4: 08/31/00. +. I. Vs. -. V. Vs. Voltage Sources. Provide potential to generate current. Ideal Voltage Source. Current determined by Circuit. Provides Voltage Independent of Current. I. Is. Is. V. Current Sources.

Download Presentation

ECE 3710 E: Circuits and Electronics

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. ECE 3710 E: Circuits and Electronics Jeff Dugger Lecture 4: 08/31/00

  2. + I Vs - V Vs Voltage Sources Provide potential to generate current Ideal Voltage Source Current determined by Circuit Provides Voltage Independent of Current

  3. I Is Is V Current Sources Ideal Current Source Provides Current Independent of Voltage Voltage is determined by the Circuit

  4. 1 1 + R R V I = - Units: Ohms ( ) = Volts / Amp (V/A) Ohm’s Law and Resistance I V = I R I R V OR V

  5. 1 + R - Ohm’s Law and Conductance I V = I R G I V = G OR V V I = G Units: Siemens ( S ) = Amps / Volt (A/V)

  6. Apply KVL: -Vs + V1 + V2 + V3 = 0 V1 Vs = V1 + V2 + V3 Apply Ohm’s Law: I V2 Vs = R1 I + R2 I + R3 I = (R1 + R2 + R3) I Define Equivalent Resistance: Req = R1 + R2 + R3 V3 Vs = Req I Series Resistance R1 Vs R2 R3

  7. Apply Ohm’s Law: V2 = R2 I Use Equivalent Resistance to find I: Substitute: I = Vs R2 1 V2 = Vs R1 + R2 R1 + R2 Voltage Divider V1 R1 Vs I V2 R2

  8. Apply KCL: Is = I1 + I2 + I3 Apply Ohm’s Law: Is = G1 V + G2 V + G3 V G1 = = (G1 + G2 + G3 ) V G2 = I1 I2 I3 V G3 = Define Equivalent Conductance: 1 1 1 Geq = G1 + G2 + G3 R2 R3 R1 Is = Geq V Parallel Resistance R1 R2 R3 Is

  9. 1 1 1 1 R3 R2 R1 Geq 1 Req = = 1 / R1 + 1 / R2 + 1 / R3 Parallel Resistance Apply KCL: Is = I1 + I2 + I3 G1 = G2 = R1 R2 R3 I1 I2 I3 Is V G3 = Or, Define Equivalent Resistance: V = Req Is

  10. Apply Ohm’s Law: I2 = G2 V Use Equivalent Conductance to find V: V = Is Substitute: G2 1 I2 = Is G1 + G2 G1 + G2 Current Divider R1 R2 I1 I2 Is V

  11. V = Is R1 1 I2 = Is R1 + R2 G1 + G2 Current Divider Apply Ohm’s Law: I2 = G2 V Use Equivalent Conductance to find V: R1 R2 I1 I2 Is V Substitute: Or, in terms or Resistance:

  12. Series-Parallel Circuit V1 R1 I1 Vs V3 R2 I2 R3 I3

  13. Series-Parallel Circuit I1 Vs V3 R2 I2 R3 I3 R1 V1

  14. Circuit Analysis Example R4 R2 R5 I V Vs I2 R3 R1

  15. Circuit Analysis Example R4 R5 I V Vs I2 R3 Ra Series Combination: Ra = R1 + R2

  16. Circuit Analysis Example Rb I V Vs I2 R3 Ra Parallel Combination: Rb = R4 || R5

  17. Circuit Analysis Example Rb I Vs Ra R3 V I2

  18. Gb 1 Is V = Vs + Ga + Gb Ga + Gb Circuit Analysis Example Rb KCL at this node I Vs Ra R3 V Is Is = Ga V + Gb(V - Vs) = (Ga + Gb) V - Gb Vs

  19. Ra Ra + Rb V = Vs + Ra || Rb Is Circuit Analysis Example Rb KCL at this node I Vs Ra R3 V Is Is = Ga V + Gb(V - Vs) = (Ga + Gb) V - Gb Vs

  20. R = I Any voltage No current V R = 0 I Any current No voltage V Open and Short Circuits “Open Circuit” R very large “Short Circuit” R very small

More Related