1 / 13

SEE 3433 MESIN ELEKTRIK

SEE 3433 MESIN ELEKTRIK. SYNCHRONOUS MACHINES - Equivalent circuit - - Phasor diagrams -. Per phase equivalent circuit. Steady state conditions:. Rotor rotates at constant speed. Steady state voltage and current in stator and rotor. Transients will not be considered.

Download Presentation

SEE 3433 MESIN ELEKTRIK

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. SEE 3433 MESIN ELEKTRIK SYNCHRONOUS MACHINES- Equivalent circuit -- Phasor diagrams -

  2. Per phase equivalent circuit Steady state conditions: Rotor rotates at constant speed Steady state voltage and current in stator and rotor Transients will not be considered

  3. Excitation voltage, Ef Per phase equivalent circuit Field current in rotor circuit produces sinusoidal distributed flux When rotor rotates, the flux will rotate, f Rotating finduces EMF in stator circuit Current in stator circuit , Ia, produces flux, a Flux that does not link rotor circuit i.e. leakage flux, al Flux that links rotor circuit i.e. Armature reaction flux, ar

  4. Per phase equivalent circuit induces voltage, Ear in the stator circuit arcombines with f producing resultant flux, r r = ar + f In terms of voltages induced, this can be written as: Er = Ear + Ef ar

  5. f r Ef ar Ia Ear Er Per phase equivalent circuit r = ar + f Er = Ear + Ef

  6. f  Ear + r + Er  f + Ef  Ef If ar Ia Ear Er Per phase equivalent circuit r = ar + f Er = Ear + Ef

  7. Ia ar Ear - Ear Per phase equivalent circuit - Ear leads Is by 90o hence can be represented by a voltage across an inductor Er = Ear + Ef Ef = Er  Ear Ef = Er + Ia jXar

  8. Ia f If Per phase equivalent circuit - Ear leads Is by 90o hence can be represented by a voltage across an inductor Ef = Er + Ia jXar

  9. f + Er   Ear + + Ef  If Per phase equivalent circuit - Ear leads Is by 90o hence can be represented by a voltage across an inductor Ef = Er + Ia jXar jXar Ia

  10. jXal Ra f + Er  + Ea  + Vt  If Per phase equivalent circuit - Ear leads Is by 90o hence can be represented by a voltage across an inductor Ef = Er + Ia jXar jXar Ia + Ef  The leakage in a is represented by a leakage reactance Xal The stator winding resistance is represented by Ra

  11. jXal Ra f + Er  + Ea  + Vt  If Per phase equivalent circuit In per phase equivalent circuit, Xar and Xal is combined as Xs Xs = Xar + Xal = synchronous reactance jXar jXs + Ea  Ia + Ef 

  12. jXs Ra Synchronous generator + Vt  Ia + Ef  Ef Ia jXa   Vt IaRa Ia Phasor diagrams Ef= Efo= Vt+ IaRa + IajXs Taking Vtas reference, i.e Vt = Vt 0o Assume Ia lags Vt by angle   Is known as the power angle

  13. jXs Ra Synchronous motor + Vt  Ia + Ef  IaRa  Vt  Ia Ia jXa Ef Phasor diagrams Vt= Ef+ IaRa + IajXs Ef= Vt- IaRa - IajXs Taking Vtas reference, i.e Vt = Vt 0o Assume Ia lags Vt by angle 

More Related