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Revision Junior Algebra

Revision Junior Algebra. I think of a number, add eight and the result is twelve. Remember to balance your equation. What you do to one side of equals you must do to the other side. (balance your equation). Write the answer for your variable.

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Revision Junior Algebra

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  1. Revision Junior Algebra I think of a number, add eight and the result is twelve. Remember to balance your equation. What you do to one side of equals you must do to the other side. (balance your equation) Write the answer for your variable. Some results are obvious as you can add and subtract in your head, but the process is important as the problems get more difficult. I think of a number, subtract eight and the result is twelve. Remember to balance your equation. What you do to one side of equals you must do to the other side. (balance your equation) Write the answer for your variable. Here are words we use with Algebra. Expression Like terms Equation Solve Expand Take out of brackets Factorise Put into brackets Variable Use a letter

  2. Revision Junior Algebra Four times a number, add ten and the result is twenty six. What is my number? What you do to one side of equals you must do to the other side, (balance your equation). 4 lots of x equals 16 So one x equals 4. Write the answer for your variable. Writing down a process is important as it makes it easier for you to find an error if you should make one.

  3. Revision Junior Algebra Write equations for the following word problems and solve. Five times a number, add ten and the result is thirty five. I take ten away from my number and the result is fifteen. One quarter of my number is twelve. Twice my number and subtract eight gives me eighteen. Three tenths of my number plus ten gives a result of 40.

  4. Revision Junior Algebra Solve the following equations. 1. 2 3 4 5 Answers on next slide

  5. Revision Junior Algebra Solve the following equations. 1. 2 3 4 5

  6. Revision Junior Algebra Solve the following equations with x on each side of equals. Balance the equation by subtracting 5 from both sides And 2x from both sides. Balance equation (divide by HCF) You should end with x =

  7. Revision Junior Algebra Solve the following equations. 1. 2 3 4 5

  8. Revision Junior Algebra Solve the following equations. 1. 2 3 4 5

  9. Revision Junior Algebra Solve the following equations. Multiply both sides by 3, why? balance Multiply by reciprocal Write as x =

  10. Revision Junior Algebra Solve the following equations. 1. 2 3 4

  11. Revision Junior Algebra Solve the following equations. 1. 2 3 4

  12. Revision Junior Algebra Solve the following equations with brackets. Divide by common factor, 3 Expand bracket Solve solve You can use either method, it depends on how well you know your tables. You have to be able to recognise common factors.

  13. Revision Junior Algebra Solve the following equations with brackets. 1. 2 3 4 5 These get progressively more difficult.

  14. Revision Junior Algebra Solve the following equations. 1. 2 3 4 5 Review your text book Chapter 14 Youtube solving equations ixl.com Bitesizemaths.co.uk Or use the The NZ Centre of Mathematics worksheets

  15. Revision Junior Algebra Solve the following equations. All sides are the same length. If one side is (x + 4)cm and the perimeter is 70cm, what is the value of x? Hint write an equation first. Solve the equation. You now have a value for x cm.

  16. Revision Junior Algebra Solve the following equations. All sides are the same length. If one side is (x + 4)cm and the perimeter is 70cm, what is the value of x? Hint write an equation first. Solve the equation. You now have a value for x cm. Either way

  17. Revision Junior Algebra Solve the following equations. If the perimeter of the shape L is 104 cm what is the value of x? If you know the value of x then work out the area of L.

  18. Revision Junior Algebra Solve the following equations. If the perimeter of the shape L is 104 cm what is the value of x? x + x + 6 + 2 + 2x + 2 + x + 2x + x + 6 = 104 8x + 16 = 104 8x = 88 x = 11 If you know the value of x then work out the area of L. Area = x x (3x +6) 11 x 39 = 426 cm2 Plus 2 x 22 = 44 cm2 Total = 470 cm2

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