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PHYSICS. Applied Mechanics. liquid / gas. Pressure in a fluid. At sea level, pressure = p atm. h 1. p 1 = p atm + gh 1. pressure increases with depth. h 2. p 2 = p atm + gh 2. p = gh. x. container. Quick Check. p = gh. liquid.
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PHYSICS Applied Mechanics
liquid / gas Pressure in a fluid At sea level, pressure = patm h1 p1 = patm + gh1 pressure increases with depth h2 p2 = patm + gh2 p = gh
x container Quick Check p = gh liquid Which graph shows how the pressure p varies with height x above the base of the container? A B C D p p p p x x x x
x container Quick Check p = gh Liquid Liquid of twice density Which graph shows how the pressure p varies with height x above the base of the container? A B C D p p p p x x x x
Upthrust At sea level, pressure = patm h1 low pressure p1 = patm + gh1 pressure increases with depth h2 p2 = patm + gh2 p = gh HIGH PRESSURE UPTHRUST
Upthrust UPTHRUST
Calculate upthrust How to calculate the upthrust? UPTHRUST
Upthrust = weight of fluid displaced weight of fluid displaced = upthrust
Upthrust = weight of fluid displaced spring balance T = 9 N T = 6 N T = 5 N 9 N 9 N W = 9 N U = 3 N U = 4 N weighing machine
Upthrust = weight of fluid displaced patm+ patm+ gh2
Upthrust = weight of fluid displaced Quick Check 2
Principle of flotation When upthrust = weight, object floats
Principle of flotation Object may float totally immersed
Principle of flotation But what if the object is totally immersed and the upthrust is still less than the weight?
Principle of flotation upthrust = weight When upthrust = weight, object floats
Principle of flotation What if the object is pushed down underwater and let go … What will happen? upthrust > weight
Principle of flotation upthrust = weight When upthrust becomes equal to weight, object floats
Principle of flotation Upthrust depends on how much volumeis immersed / displaced When upthrust = weight, object floats in equilibrium
Three objects of equal volume are in equilibrium A Quick Check B C
When object is not moving, the friction is called static friction. Friction When object is moving, the friction is called kinetic friction.
Viscous force • When object is moving inside a fluid, it experiences viscous force • e.g. air resistance, water resistance water air As water is denser than air, object will hit more water molecules than air molecules, so water resistance > air resistance
Viscous force increases with speed • The faster the object moving, • the greater the force in hitting the molecules, • the greater the resistance. water air
v t Terminal Velocity (object falling in air) Object released from rest: v = 0 m s-1 a = g = 9.81 m s-2 mg Fv v = 3 m s-1 a = 4 m s-2 mg
Terminal Velocity (object falling in air) Object released from rest: v = 0 m s-1 a = g = 9.81 m s-2 mg v Fv v = 3 m s-1 a = 4 m s-2 mg Fv t v = 4 m s-1 a = 2 m s-2 mg
Terminal Velocity (object falling in air) Object released from rest: v = 0 m s-1 a = g = 9.81 m s-2 mg v Fv terminal velocity v = 3 m s-1 a = 4 m s-2 mg Fv t v = 4 m s-1 a = 2 m s-2 mg Fv v = 5 m s-1 a = 0 m s-2 mg
Object released and falling in vacuum in air Quick Check After fallen distance x tair vair aair t0 v0 a0
Falling vs moving up in air moving up in air falling in air Fv Fv v v mg mg viscous force opposite to weight viscous force and weight same direction lesser accelerating force greater decelerating force
Quick Check a = initial deceleration t = time to reach the top s = maximum height u u in air in vacuum object thrown up with same speed at same height
50 m 50 m t = 1 s 50 m s-1 Projectile Motion When t = 1 s, sx = 50 1 = 50 m
50 m 50 m t = 1 s 50 m s-1 Projectile Motion sy = uyt + ½gt2 = 0 + ½g(1)2 = 5 m
50 m 50 m t = 2 s sx = uxt = 50 2 = 100 m sy = uyt + ½gt2 = 0 + ½g(2)2 = 20 m 50 m s-1 Projectile Motion
50 m 50 m t = 3 s sx = uxt = 50 3 = 150 m sy = uyt + ½gt2 = 0 + ½g(3)2 = 45 m 50 m s-1 Projectile Motion
50 m 50 m t = 4 s sx = uxt = 50 4 = 200 m sy = uyt + ½gt2 = 0 + ½g(4)2 = 80 m 50 m s-1 Projectile Motion
50 m 50 m t = 5 s sx = uxt = 50 5 = 250 m sy = uyt + ½gt2 = 0 + ½g(5)2 = 125 m 50 m s-1 Projectile Motion
50 m 50 m t = 6 s sx = uxt = 50 6 = 300 m sy = uyt + ½gt2 = 0 + ½g(6)2 = 180 m 50 m s-1 Projectile Motion
50 m 50 m 50 m s-1 Projectile Motion (with air resistance)
Question to think about… Suppose You have some ice floating in a glass of water. When the ice melts, does the water level A rise B fall C stay the same
Question to think about… Suppose you are on a boat floating in a lake. A large stone is on the boat. You take the stone and drop it into the water. Will the water level A rise B fall C stay the same