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Volume. Volume of Rectangular Solids. 1,000 mL. 1 L. 1 cm³. Measuring the Volume of Solid or Irregular Objects. How can the volume of a solid object such as a shoebox be measured?. To measure solid objects that are regular shape, a formula for volume can be applied.
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Volume Volume of Rectangular Solids
1,000 mL 1 L 1 cm³
How can the volume of a solid object such as a shoebox be measured? • To measure solid objects that are regular shape, a formula for volume can be applied
The formula for calculating the volume of a rectangular object is: Volume = Length x Width x Height Volume = L x W x H Volume = 3cm x 15cm x 4cm Volume = 180 cm³
Why is the unit cm³ used when calculating the volume of a rectangular object? • When multiplying the object’s length, width and height, the cm units are also multiplied by 3 Example: cm x cm x cm = cm³
The SI unit known for measuring solids with a larger volume is known as the… • Cubic meter = m³
What is a cubic meter? • The SI unit used to measure solids with a larger volume • A cubic meter is equal to the volume of a cube that measures 1 meter on each side m x m x m = m³ • Hint: Think of a big box whose 3 sides measure 1 meter each
Suppose a cereal box is 10 centimeters long, 4 centimeters wide, and 20 centimeters high. What would be the volume of the box? Volume = Length x Width x Height Volume = 10 cm x 4 cm x 20 cm Volume = 800 cm³
Volume Volume of Irregular Solids
How is the volume of an irregular solid such as a rock measured? • To measure the volume of an irregular solid, immerse the object in water, and measure how much the water level rises • This method is called the: Water Displacement Method
How does the water displacement method work? 1.Record the volume of water in the first beaker or graduated cylinder Example: 20 ml 2. Carefully place the irregular solid into the water. Record the volume of the water plus the object Example: Now the volume is 32 ml 3.Subtract the volume of the water alone from the volume of the water plus the object Example: 32 ml – 20 ml = 12 ml
Water Displacement Problem • The graduated cylinder has 22 ml of water • When you add the rock, the water rises to 33 ml. • What is the volume of the rock? • 33 ml – 22 ml = 11ml The volume of the rock is 11 ml