1 / 30

Rosen 1.3

Predicate Calculus. Rosen 1.3. Propositional Functions. Propositional functions (or predicates) are propositions that contain variables. Ex: Let P(x) denote x > 3 P(x) has no truth value until the variable x is bound by either assigning it a value or by quantifying it.

rbrinkman
Download Presentation

Rosen 1.3

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Predicate Calculus Rosen 1.3

  2. Propositional Functions • Propositional functions (or predicates) are propositions that contain variables. • Ex: Let P(x) denote x > 3 • P(x) has no truth value until the variable x is bound by either • assigning it a value or by • quantifying it.

  3. Assignment of values Let Q(x,y) denote “x + y = 7”. Each of the following can be determined as T or F. Q(4,3) Q(3,2) Q(4,3)  Q(3,2) [Q(4,3)  Q(3,2)]

  4. Quantifiers Universe of Discourse, U: The domain of a variable in a propositional function. Universal Quantification of P(x) is the proposition:“P(x) is true for all values of x in U.” Existential Quantification of P(x) is the proposition: “There exists an element, x, in U such that P(x) is true.”

  5. Universal Quantification of P(x) xP(x) “for all x P(x)” “for every x P(x)” Defined as: P(x0)  P(x1)  P(x2)  P(x3)  . . . for all xi in U Example: Let P(x) denote x2  x If U is x such that 0 < x < 1 then xP(x) is false. If U is x such that 1 < x then xP(x) is true.

  6. Existential Quantification of P(x) xP(x) “there is an x such that P(x)” “there is at least one x such that P(x)” “there exists at least one x such that P(x)” Defined as: P(x0)  P(x1)  P(x2)  P(x3)  . . . for all xi in U Example: Let P(x) denote x2  x If U is x such that 0 < x  1 then xP(x) is true. If U is x such that x < 1 then xP(x) is true.

  7. Quantifiers • xP(x) • True when P(x) is true for every x. • False if there is an x for which P(x) is false. • xP(x) • True if there exists an x for which P(x) is true. • False if P(x) is false for every x.

  8. Negation (it is not the case) • xP(x) equivalent to xP(x) • True when P(x) is false for every x • False if there is an x for which P(x) is true. •  xP(x) is equivalent to xP(x) • True if there exists an x for which P(x) is false. • False if P(x) is true for every x.

  9. Examples 2a Let T(a,b) denote the propositional function “a trusts b.” Let U be the set of all people in the world. Everybody trusts Bob. xT(x,Bob) Could also say: xU T(x,Bob)  denotes membership Bob trusts somebody. xT(Bob,x)

  10. Examples 2b Alice trusts herself. T(Alice, Alice) Alice trusts nobody. x T(Alice,x) Carol trusts everyone trusted by David. x(T(David,x)  T(Carol,x)) Everyone trusts somebody. x y T(x,y)

  11. Examples 2c x y T(x,y) Someone trusts everybody. y x T(x,y) Somebody is trusted by everybody. Bob trusts only Alice. x (x=Alice  T(Bob,x))

  12. Bob trusts only Alice.x (x=Alice  T(Bob,x)) Let p be “x=Alice” q be “Bob trusts x” p q p  q T T T T F F F T F F F T True only when Bob trusts Alice or Bob does not trust someone who is not Alice

  13. Quantification of Two Variables(read left to right) • xyP(x,y) or yxP(x,y) • True when P(x,y) is true for every pair x,y. • False if there is a pair x,y for which P(x,y) is false. • xyP(x,y) or yxP(x,y) • True if there is a pair x,y for which P(x,y) is true. • False if P(x,y) is false for every pair x,y.

  14. Quantification of Two Variables • xyP(x,y) • True when for every x there is a y for which P(x,y) is true. • (in this case y can depend on x) • False if there is an x such that P(x,y) is false for every y. • yxP(x,y) • True if there is a y for which P(x,y) is true for every x. • (i.e., true for a particular y regardless (or independent) of x) • False if for every y there is an x for which P(x,y) is false. • Note that order matters here • In particular, if yxP(x,y) is true, then xyP(x,y) is true. • However, if xyP(x,y) is true, it is not necessary that yxP(x,y) is true.

  15. Examples 3a Let L(x,y) be the statement “x loves y” where U for both x and y is the set of all people in the world. Everybody loves Jerry. xL(x,Jerry) Everybody loves somebody. x yL(x,y) There is somebody whom everybody loves. yxL(x,y)

  16. Examples 3b1 There is somebody whom Lydia does not love. xL(Lydia,x) Nobody loves everybody. (For each person there is at least one person they do not love.) xyL(x,y) There is somebody (one or more) whom nobody loves y x L(x,y)

  17. Examples 3b2 There is exactly one person whom everybody loves. xyL(y,x)? No. There could be more than one person everybody loves x{yL(y,x)  w[(yL(y,w))  w=x]} If there are, say, two values x1 and x2 (or more) for which L(y,x) is true, the proposition is false. x{yL(y,x)  w[(yL(y,w))  w=x]}? xw[(y L(y,w))  w=x]?

  18. Examples 3c There are exactly two people whom Lynn loves. x y{xy  L(Lynn,x)  L(Lynn,y)}? No. x y{xy  L(Lynn,x)  L(Lynn,y)  z[L(Lynn,z) (z=x  z=y)]} Everyone loves himself or herself. xL(x,x) There is someone who loves no one besides himself or herself. xy(L(x,y)  x=y)

  19. Thinking of Quantification as Loops • Quantifications of more than one variable can be thought of as nested loops. • For example, xyP(x,y) can be thought of as a loop over x, inside of which we loop over y (i.e., for each value of x). • Likewise, xyP(x,y) can be thought of as a loop over x with a loop over y nested inside. This can be extended to any number of variables.

  20. Quantification as Loops • Using this procedure • xyP(x,y) is true if P(x,y) is true for all values of x,y as we loop through y for each value of x. • xyP(x,y) is true if P(x,y) is true for at least one set of values x,y as we loop through y for each value of x. • …And so on….

  21. Quantification of 3 Variables • Let Q(x,y,z) be the statement “x + y = z”, where x,y,z are real numbers. • What is the truth values of • xyzQ(x,y,z)? • zxyQ(x,y,z)?

  22. Quantification of 3 Variables • Let Q(x,y,z) be the statement “x + y = z”, where x,y,z are real numbers. • xyzQ(x,y,z) • is the statement, “For all real numbers x and for all real numbers y, there is a real number z such that • x + y = z.” True

  23. Quantification of 3 Variables Let Q(x,y,z) be the statement “x + y = z”, where x,y,z are real numbers. zxyQ(x,y,z) is the statement, “There is a real number z such that for all real numbers x and for all real numbers y, x + y = z.” False

  24. Examples 4a Let P(x) be the statement: “x is a Georgia Tech student” Q(x) be the statement: “ x is ignorant” R(x) be the statement: “x wears red” and U is the set of all people. No Georgia Tech students are ignorant. x(P(x) Q(x)) x(P(x) Q(x)) OK byImplication equivalence. x(P(x)  Q(x)) Does not work. Why?

  25. Examples 4a No Georgia Tech students are ignorant. x(P(x) Q(x)) • x(P(x)  Q(x)) • x (P(x)  Q(x)) Negation equivalence • x ( P(x)  Q(x)) Implication equivalence • x (  P(x)   Q(x)) DeMorgans • x ( P(x)   Q(x)) Double negation Only true if everyone is a GT student and is not ignorant.

  26. Examples 4a P(x) be the statement: “x is a Georgia Tech student” Q(x) be the statement: “ x is ignorant” R(x) be the statement: “x wears red” and U is the set of all people. No Georgia Tech students are ignorant. x(P(x)  Q(x)) Also works. Why?

  27. Examples 4a No Georgia Tech students are ignorant. x(P(x) Q(x)) • x(P(x)  Q(x)) •  x (P(x)  Q(x)) Negation equivalence • x (P(x)  Q(x)) DeMorgan • x (P(x) Q(x)) Implication equivalence

  28. Examples 4b Let P(x) be the statement: “x is a Georgia Tech student” Q(x) be the statement: “ x is ignorant” R(x) be the statement: “x wears red” and U is the set of all people. All ignorant people wear red. x(Q(x) R(x))

  29. Examples 4c Let P(x) be the statement: “x is a Georgia Tech student” Q(x) be the statement: “ x is ignorant” R(x) be the statement: “x wears red” and U is the set of all people. No Georgia Tech student wears red. x(P(x) R(x)) What about this? x(R(x)  P(x))

  30. Examples 4d If “no Georgia Tech students are ignorant” and “all ignorant people wear red”, does it follow that “no Georgia Tech student wears red?” x((P(x) Q(x))  (Q(x) R(x))) NO Some misguided GT student might wear red!! This can be shown with a truth table or Wenn diagrams

More Related