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Total Mixed Ration (TMR) for Dairy Cows Dr. István HULLÁR associate professor (2010)

Total Mixed Ration (TMR) for Dairy Cows Dr. István HULLÁR associate professor (2010). - M ixture of forages, roughages, grains, extr. meals, supplements, etc., - fed according to the total dai ly requirement s of production groups. TMR. Control of the TMR. TASK

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Total Mixed Ration (TMR) for Dairy Cows Dr. István HULLÁR associate professor (2010)

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  1. Total Mixed Ration (TMR) for Dairy CowsDr. István HULLÁR associate professor (2010)

  2. - Mixture of forages, roughages, grains, extr. meals, supplements, etc., - fed according to the total daily requirements of production groups. TMR

  3. Control of the TMR TASK Check the following TMR whether it is sufficient for the following dairy cow. STEPS of Solution 1. Data Sheet - TMR, - data regarding the dairy cow; 2. Nutrient Requirements 3. Nutrient Content of the TMR 4. Evaluation (requirements vs. TMR), Corrections.

  4. Control of the TMR 1. Data Sheet - TMR meadow hay (average): 5.0 kg, corn silage (predough stage): 15.5 kg sunflower meal extr. (average): 2.6 kg, CCM (Corn Cob Mix): 8.4 kg; - Data regarding the dairy cow W: 580 kg, milk production: 25 kg/day, milk protein: 3.2%, milk fat: 3.5%, 2nd lactation.

  5. Calculation of the Requirements 2. Nutrient Requirements 2.1. DMI: 2-3% of the W (580 kg) = 11.6-17.4 kg/day, 2.2. CF: 18-23% of the DM content of TMR.

  6. Calculation of the Requirements 2. Nutrient Requirements 2.3.Maintenance 2.3.1. Energy reqirement NEl = 0.3514*W0.75= 0.3514*5800.75 = 0.3514*118.19 = 41.53 MJ/day; 2.3.2.Protein requirement MP = 3.41*W0.75= 3.41*118.19 = 403 g/day; 2.3.3. Ca requirement: 44*0.001*W = 25.52 g/day; 2.3.4. P requirement: 34*0.001*W = 19.72 g/day.

  7. Calculation of the Requirements 2. Nutrient Requirements 2.3.Maintenance 2.3.5. Correction 1st lactation: +20% of the total maintenance req.; 2nd lactation: +10% of the total maintenance req. (see later); 2.4.Milk Production 2.4.1. Energy reqirement NEl = 1.471 + 0.4032*milk fat% = 1.471 + 0.4032*3.5 = 2.88 MJ/kg milk; 25 kg milk: 25*2.88 = 72.06 MJ/day.

  8. Calculation of the Requirements 2. Nutrient Requirements 2.4.Milk Production 2.4.2.Protein requirement MP = milk protein (g)/0.65 = 32/0.65 = 49 g/kg milk; 25 kg milk: 25*49 = 1225 g/day. 2.4.3. Ca requirement: 2.8 g/kg milk; 25 kg milk = 25*2.8 = 70.00 g/day; 2.4.4. P requirement: 1.7 g/kg milk; 25 kg milk: 25*1.7 = 42.50 g/day.

  9. 2. Requirements Sum of the Requirements DM CF NEl MP Ca P (kg) (g) (MJ) (g) (g) (g) Maintenance - - 41.53 403 25.52 19.72 +10% - - 4.15 40 2.55 1.97 25 kg milk - - 72.06 1225 70.00 42.50 TOTAL 11.6-17.4 18-23% of DM 117.74 1668 98.07 64.19

  10. 3. Nutrient Content of the TMR DM CF NEl MPE MPN Ca P Feeds (kg) (g) (MJ) (g) (g) (g) (g) 5.0 kg hay 4.37 1372 21.84 415 371 20.98 12.24 15.5 kg silage 5.41 1087 34.73 395 298 17.85 13.52 2.6 kg sunfl. 2.33 417 14.79 333 608 7.22 17.47 8.4 kg CCM 5.28 312 41.13 491 306 3.17 13.20 TOTAL 17.39 3188 112.46 1634 1583 49.22 56.43 Which MP value is valid? 

  11. 4. Evaluation, Corrections Requirements TMR Evaluation DM, kg 11.60-17.40 17.39 O.K. CF, g 18-23% of the DM 3.188/17.39*100 = 18.33% O.K. Other Nutrients The tolerable difference between the requirement and the TMR: the rquirement of 2 kg milk ().

  12. 4. Evaluation, Corrections NEl (MJ) Requirement: 117.74 TMR: 112.46 Difference: - 5.28 Tolerable level: 2.88*2 =  5.76 Evaluation: O.K. MP (g) Requirement: 1668 TMR: 1583 Difference: - 85 Tolerable level: 49*2 =  98 Evaluation: O.K.

  13. 4. Evaluation, Corrections Ca (g) Requirement: 98.07 TMR: 49.22 Difference: - 48.85 Tolerable level: 2.8*2 =  5.6 Evaluation: insufficient P (g) Requirement: 64.19 TMR: 56.43 Difference: - 7.76 Tolerable level: 1.7*2 =  3.4 Evaluation: insufficient.

  14. 4. Evaluation, Corrections Corrections Types of Ca and P supplements Name Ca (g) P (g) Limestone 380 - AP-17 210 170 AP-18 190 180 Phylafor 40 125 AP-IV 17 170

  15. 4. Evaluation, Corrections Corrections 1. Correction of the P deficiency by AP-IV: 1000 g AP-IV contains 170 g P x g AP-IV contains 7.76 g P x = 7.76/170*1000 = 45.65 g AP-IV 2. Calculation of the amount of Ca given by AP-IV: 1000 g AP-IV contains 17 g Ca 45.65 g AP-IV contains x g Ca x = 45.65/1000*17 = 0.78 g Ca.

  16. 4. Evaluation, Corrections Corrections 3. Calculation of the Ca deficiency remained: 48.85 – 0.78 = 48.07 g; 4. Correction of the Ca deficiency by limestone: 1000 g limestone contains 380 g Ca x g limestone contains 48.07 g Ca x = 48.07/380*1000 = 126.50 g limestone.

  17. 4. Evaluation, Corrections Final Evaluation - DM, CF, NEl, and MP content of the TMR are O.K.; - but 45.65 g AP-IV and 126.50 g limestone supplementations are required.

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