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EXAMPLE 1

Write a two-column proof for the situation in Example 4 on page 107. m ∠ 1 = m ∠ 3. GIVEN:. m ∠ EBA = m ∠ DBC. PROVE:. REASONS. STATEMENT. 1. 1. m ∠ 1 = m ∠ 3. Given. 2. Angle Addition Postulate. 2. m ∠ EBA = m ∠ 3 + m ∠ 2. 3.

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EXAMPLE 1

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  1. Write a two-column proof for the situation in Example 4 on page 107. m∠ 1=m∠ 3 GIVEN: m∠ EBA= m∠ DBC PROVE: REASONS STATEMENT 1. 1. m∠ 1=m∠ 3 Given 2. Angle Addition Postulate 2. m∠ EBA =m∠ 3 + m∠ 2 3. Substitution Property of Equality 3. m∠ EBA=m∠ 1 + m∠ 2 EXAMPLE 1 Write a two-column proof

  2. 4. Angle Addition Postulate m∠ EBA= m∠ DBC 5. 5. Transitive Property of Equality EXAMPLE 1 Write a two-column proof 4. m∠ 1 +m∠ 2 = m∠ DBC

  3. 1. Four steps of a proof are shown. Give the reasons for the last two steps. REASONS STATEMENT 1. 1. AC = AB + AB Given 2. 2. AB + BC = AC Segment Addition Postulate ? 3. 3. AB + AB = AB + BC ? 4. 4. AB = BC for Example 1 GUIDED PRACTICE GIVEN :AC = AB + AB PROVE :AB = BC

  4. ANSWER GIVEN :AC = AB + AB PROVE :AB = BC REASONS STATEMENT 1. 1. AC = AB + AB Given 2. 2. AB + BC = AC Segment Addition Postulate 3. 3. AB + AB = AB + BC Transitive Property of Equality 4. 4. AB = BC Subtraction Property of Equality for Example 1 GUIDED PRACTICE

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