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Unit 6 Ch. 10.2, 11.4 and 11.5. Warm up Homework check Notes – Central Angles and Arcs Circumference and Arc Length Areas of Circles and Sectors. 127° 60° 83° 173° 34° 136° 83° 107° 24 A. 270° B. 27 min C. 37 min D 100°.
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Unit 6 Ch. 10.2, 11.4 and 11.5 • Warm up • Homework check • Notes – Central Angles and Arcs Circumference and Arc Length Areas of Circles and Sectors
127° • 60° • 83° • 173° • 34° • 136° • 83° • 107° • 24 A. 270° • B. 27 min • C. 37 min • D 100° Homework 10.2 Central Angles • 80° • 165° • 258° • 195° • 80° • 110° • 90° • 70° • 57° • 57°
10.2 Central angles and arcs • An angle whose vertex is at the center of the circle and is formed by two radii. • The intercepted arc has the same measure as the central angle R Major arc
The circumference of a circle is ___________ or ___________, where d is the diameter of the circle and r is the radius of the circle.
Example 1 So we need to find the circumference and then multiply times 15. First we will need the radius or diameter. d = 5.5+15+5.5 =26in Second find the Circumference Last multiply the Circumference times 15. Distance = 15*81.68 =1225.2 inches about 102 feet
Arc length • An ____________ is a portion of the circumference of a circle. You can use the measure of the arc (in degrees) to find its length (in linear units).
Try these on your own. About 15.71 in, about 5.41 ft About 68 revolutions About 81.68 m About 4.01 ft About 5.89 yds
Formulas: Area of a Circle: Area of a Sector:
20(28) – 122 – = area to paint 560 – 144 – = area to paint Example 4 Area of rectangle – area of square – area of semicircle = area of wall to paint 359.45 ≈ area to paint So the answer is C. 359 ft2
Try these on your own. 196 or about 615.75 sq ft About 205.25 sq ft About 410.50 sq ft About 907.92 sq cm About 43.74 sq m
Geometry homework WS 11.4-11.5